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3 years ago

5

Find the first three iterates of the function f(z) = 2z + (3 - 2i) with an initial value of zo = 5i.

1 answer:

Ratling [72]3 years ago

3 0

Answer:

C

Step-by-step explanation:

Saw it on a quizlet

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Initially a tank contains 10 liters of pure water. Brine of unknown (but constant) concentration of salt is flowing in at 1 lite

zhenek [66]

Answer:

Therefore the concentration of salt in the incoming brine is 1.73 g/L.

Step-by-step explanation:

Here the amount of incoming and outgoing of water are equal. Then the amount of water in the tank remain same = 10 liters.

Let the concentration of salt be a gram/L

Let the amount salt in the tank at any time t be Q(t).

$\frac{dQ}{dt} =\textrm {incoming rate - outgoing rate}$

Incoming rate = (a g/L)×(1 L/min)

=a g/min

The concentration of salt in the tank at any time t is = $\frac{Q(t)}{10}$ g/L

Outgoing rate = $(\frac{Q(t)}{10} g/L)(1 L/ min)$ $\frac{Q(t)}{10} g/min$

$\frac{dQ}{dt} = a- \frac{Q(t)}{10}$

$\Rightarrow \frac{dQ}{10a-Q(t)} =\frac{1}{10} dt$

Integrating both sides

$\Rightarrow \int \frac{dQ}{10a-Q(t)} =\int\frac{1}{10} dt$

$\Rightarrow -log|10a-Q(t)|=\frac{1}{10} t +c$ [ where c arbitrary constant]

Initial condition when t= 20 , Q(t)= 15 gram

$\Rightarrow -log|10a-15|=\frac{1}{10}\times 20 +c$

$\Rightarrow -log|10a-15|-2=c$

Therefore ,

$-log|10a-Q(t)|=\frac{1}{10} t -log|10a-15|-2$ .......(1)

In the starting time t=0 and Q(t)=0

Putting t=0 and Q(t)=0 in equation (1) we get

$- log|10a|= -log|10a-15| -2$

$\Rightarrow- log|10a|+log|10a-15|= -2$

$\Rightarrow log|\frac{10a-15}{10a}|= -2$

$\Rightarrow |\frac{10a-15}{10a}|=e ^{-2}$

$\Rightarrow 1-\frac{15}{10a} =e^{-2}$

$\Rightarrow \frac{15}{10a} =1-e^{-2}$

$\Rightarrow \frac{3}{2a} =1-e^{-2}$

$\Rightarrow2a= \frac{3}{1-e^{-2}}$

$\Rightarrow a = 1.73$

Therefore the concentration of salt in the incoming brine is 1.73 g/L

8 0

3 years ago

Find the value of X

olchik [2.2K]

<h3>Answer: 112</h3>

=========================================================

Explanation:

The angle adjacent to the 146 degree angle is 180-146 = 34 degrees.

In other words, the angles 34 and 146 combine to 180. These angles are supplementary.

The tickmarks on this triangle tell us it is isosceles. The angles opposite the congruent sides are congruent angles. So the unmarked interior angles (not marked x) are 34 degrees each.

Now use the fact that any triangle has its interior angles always add to 180

x+34+34 = 180

x+68 = 180

x = 180-68

x = 112

5 0

3 years ago

Bella pays 7 payments of $5 each to a game store.she returns one game receives $20 back.what is the change of the about of money

hichkok12 [17]

15$ would be ya answer ....

6 0

3 years ago

Write an equation of the line in slope-intercept form: y-intercept of 2, x-intercept of 4

zvonat [6]

Answer:

$\sf y=-\dfrac12x+2$

Step-by-step explanation:

y-intercept is when x = 0, so (0, 2)

x-intercept is when y = 0, so (4, 0)

$\sf slope=\dfrac{change\:in\:y}{change\:in\:x}=\dfrac{0-2}{4-0}=-\dfrac12$

Slope-intercept form of linear equation: $\sf y=mx+b$

(where m is the slope and b is the y-intercept)

Given:

$\sf m=-\dfrac12$
b = 2

$\sf \implies y=-\dfrac12x+2$

3 0

2 years ago

Is -29/8 greater than -3.62

Darina [25.2K]

-3.62 is greater than -29/8

5 0

3 years ago