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3 years ago

Solve the equation for y. 8x – 9y = 11

1 answer:

6 0

8x - 9y = 11 (subtract 8x from each side)

- 9y = -8x + 11 (divide -9 from each side)

$\frac{-9y}{-9} = \frac{-8x+11}{-9}$

y = $\frac{-8}{-9} x - \frac{11}{9}$

D. $y=\frac{8}{9} x - \frac{11}{9}$

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Pls solve the simultaneous equation in the attachment.

siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

$\frac{x}{2}-\frac{y}{5}=1$ ----> equation A

$y-\frac{x}{3}=8$ ----> equation B

Multiply equation A by 10 both sides to remove the fractions

$5x-2y=10$ ----> equation C

isolate the variable y in equation B

$y=\frac{x}{3}+8$ ----> equation D

we have the system of equations

$5x-2y=10$ ----> equation C

$y=\frac{x}{3}+8$ ----> equation D

Solve the system by substitution

substitute equation D in equation C

$5x-2(\frac{x}{3}+8)=10$

solve for x

$5x-\frac{2x}{3}-16=10$

Multiply by 3 both sides

$15x-2x-48=30$

$15x-2x=48+30$

Combine like terms

$13x=78$

$x=6$

<em>Find the value of y</em>

$y=\frac{x}{3}+8$

$y=\frac{6}{3}+8$

$y=10$

The solution is the ordered pair (6,10)

Part b) we have

$xy=21$ ---> equation A

$x+5y=22$ ----> equation B

isolate the variable x in the equation B

$x=22-5y$ ----> equation C

substitute equation C in equation A

$(22-5y)y=21$

solve for y

$22y-5y^2=21$

$5y^2-22y+21=0$

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

$x=22-5(1.4)=15$

For y=3

$x=22-5(3)=7$

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

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3 years ago

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Roman55 [17]

Answer:

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Step-by-step explanation:

127 137

If you divide the foam into 2 rectangular prisms, you will get a rectangular prism with dimensions of 1 * 2 * 7, and another prism with dimensions of 1 * 3 * 7. You find the separate volumes of each, and get 14 ft^3, and 21 ft^3. You add these together to get 35 ft^3

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2 years ago

(a) The diagram below, not drawn to scale, shows a circle, centre 0. EH and EF are tangents to the circle. FOG and JOH are strai

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Answer:

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2 years ago

Will give brainliest to the 1st right answer!!!!

monitta

Step-by-step explanation:

c is the answer