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2 years ago

A) what value represents the 40th percentile of these returns?

1 answer:

4 0

You need to look at the scale of different values and find one which is in the 40th percentile. This means 40 percent are higher and 60 percent are lower than the value you select. This can be done by figuring out the middle and going up a bit.

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LAST ONE! PLEASE HELP ITS THE FINAL QUESTIONS FOR ME TO FINISH THIS DEATH TRAP

Sedaia [141]

6(n-50) so the answer is A I think good luck

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2 years ago

If a large tree is 22 feet tall and a smaller tree is 3/4 of the larger tree's height, then how tall is the

ad-work [718]

Answer:It should be 16.5 or 16 1/2.

Step-by-step explanation:

22•3/4

5 0

2 years ago

Question options: A.)7 B.)503 C.)6 D.)5

gavmur [86]

Answer:

x=6

Step-by-step explanation:

We can use ratios to determine the value of x

x 9

------ = ----------

10 15

Using cross products

15x = 9*10

15x = 90

Divide each side by 15

15x/15 =90/15

x = 6

3 0

2 years ago

Read 2 more answers

Solve by using proper methods.

oksano4ka [1.4K]

Answer:

Approximately after 66.15 years, there will be 100 coyotes left

Step-by-step explanation:

We can use the formula $F=P(1+r)^t$ to solve this.

Where

F is the future amount (F=100 coyotes)

P is the initial amount (P=750 coyotes)

r is the rate of decrease per year (which is -3% per year or -0.03)

t is the time in years (which we need to find)

Putting all the information into the formula we solve.

Note: The logarithm formula we will use over here is $ln(a^b)=bln(a)$

So, we have:

$F=P(1+r)^t\\100=750(1-0.03)^t\\100=750(0.97)^t\\\frac{100}{750}=0.97^t\\\frac{2}{15}=0.97^t\\ln(\frac{2}{15})=ln(0.97^t)\\ln(\frac{2}{15})=tln(0.97)\\t=\frac{ln(\frac{2}{15})}{ln(0.97)}\\t=66.15$

Hence, after approximately 66.15 years, there will be 100 coyotes left.

Rounding, we will have 66 years

4 0

2 years ago

3,15,75,375 9th term

e-lub [12.9K]

Answer:

1,171,875

Step-by-step explanation:

The sequence is multiplying by 5 every time. It will be 3, 15, 75, 375, 1875, 9375, 46,875, 234,375, and then 1,171,875

5 0

2 years ago