Answer:
Remove parentheses.
y-10=-3\times -2y−10=−3×−2
2 Simplify 3\times -23×−2 to -6−6.
y-10=-(-6)y−10=−(−6)
3 Remove parentheses.
y-10=6y−10=6
4 Add 1010 to both sides.
y=6+10y=6+10
5 Simplify 6+106+10 to 1616.
y=16y=16
Which recursive formula can be used to generate the sequence
below, where f(1) = 3 and n ≥ 1?
3, –6, 12, –24, 48
The recursive formula for this sequence is
f (n + 1) = –2 f(n)
at n=1 f(n)= 3
at n = 2
f(2) = -2 (3) = -6
n = 3
f(3) = -2 (-6) = 12 and so on
Answer:
Volume of the frustum = ⅓πh(4R² - r²)
Step-by-step explanation:
We are to determine the volume of the frustum.
Find attached the diagram obtained from the given information.
Let height of small cone = h
height of the large cone = H
The height of a small cone is a quarter of the height of the large cone:
h = ¼×H
H = 4h
Volume of the frustum = volume of the large cone - volume of small cone
volume of the large cone = ⅓πR²H
= ⅓πR²(4h) = 4/3 ×π×R²h
volume of small cone = ⅓πr²h
Volume of the frustum = 4/3 ×π×R²h - ⅓πr²h
Volume of the frustum = ⅓(4π×R²h - πr²h)
Volume of the frustum = ⅓πh(4R² - r²)
A=Lw
P=2L+2w
216=Lw
W=216/L...substitute to Perimeter equation
60=2L+2(216/L)
60L=2L^2 + 432
2L^2-60L+432=0
2(L^2 - 30L + 216)=0
2(L-18)(L-12)=0
L=12, W=18 or L=18, W=12