she will make a profit after the 12th car.
explanation- x(15−3)−145>0 to find when she starts to make a profit:
So:
12x−145>0
12x>145
x>14512=12.08≈12
if x=13:
13⋅12−145=$11
Answer:
m = 16
Step-by-step explanation:
Given expression 2m−13 and m+3.
We have to find value of m for which both the expression are equal.
To find that value we will equate both the expression and solve as given below
2m−13 = m+3
adding 13 on both LHS and RHS
2m−13 + 13 = m+3 + 13
=> 2m = m +16
subtracting m from LHS and RHS
2m - m = m +16 - m
=> m = 16
Thus, value of m will be 16.
to validate this lets put value of m as 16 in both the equation
2m - 13 = 2*16 - 13 = 32-13 = 19
m+3 = 16+3 = 19.
Thus, we see for m = 16 , both expression has equal value which is equal to 19.
Answer:
You can run 7 miles in one hour
Step-by-step explanation:
60 mins in one hour
8.5 mins for one mile
60/8.5 = 7.0588
7/8 and 3/4
Both need to have same denominator so it would be 32, in this case because 8*4 is 32.
7/32+3/32=10/32 simplified to 5/16
Answer:
All the intervals that contain the number
are solution of the problem
Step-by-step explanation:
we know that
The equation of a vertical parabola into vertex form is equal to
![f(x)=a(x-h)^{2}+k](https://tex.z-dn.net/?f=f%28x%29%3Da%28x-h%29%5E%7B2%7D%2Bk)
where
(h,k) is the vertex of the parabola
In this problem we have
![f(x)=(x+3)(x+1)](https://tex.z-dn.net/?f=f%28x%29%3D%28x%2B3%29%28x%2B1%29)
Convert to vertex form
![f(x)=x^{2}+x+3x+3](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%2Bx%2B3x%2B3)
![f(x)=x^{2}+4x+3](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%2B4x%2B3)
Group terms that contain the same variable, and move the constant to the opposite side of the equation
![f(x)-3=x^{2}+4x](https://tex.z-dn.net/?f=f%28x%29-3%3Dx%5E%7B2%7D%2B4x)
Complete the square. Remember to balance the equation by adding the same constants to each side.
![f(x)-3+4=x^{2}+4x+4](https://tex.z-dn.net/?f=f%28x%29-3%2B4%3Dx%5E%7B2%7D%2B4x%2B4)
![f(x)+1=x^{2}+4x+4](https://tex.z-dn.net/?f=f%28x%29%2B1%3Dx%5E%7B2%7D%2B4x%2B4)
Rewrite as perfect squares
![f(x)+1=(x+2)^2](https://tex.z-dn.net/?f=f%28x%29%2B1%3D%28x%2B2%29%5E2)
-------> equation in vertex form
The vertex is the point ![(-2,-1)](https://tex.z-dn.net/?f=%28-2%2C-1%29)
The x-coordinate of the vertex is ![-2](https://tex.z-dn.net/?f=-2)