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atroni [7]
3 years ago
6

Find the equation of a line passing through (-2,4) and ( 0,8)

Mathematics
1 answer:
Vlada [557]3 years ago
5 0
Eqn of line: y = mx + c
where m is the gradient and c is the y intercept
gradient = (8-4)/(0-(-2)) = 4/2 = 2
thus y = 2x + c
sub (0,8) into this eqn
8 = 2(0) + c
c = 8
eqn of line: y = 2x + 8
You might be interested in
Estimate 1.9 x 4.4
Lelechka [254]

Answer:

A

Step-by-step explanation:

1.9 about 2, and 4.4 is about 4.

2x4=8

So it is safe to say between 4 and 10.

3 0
3 years ago
7:11 and 21:33 yes or no
grandymaker [24]
Yes!! They both are equivalent.....
7 0
3 years ago
I need to know how to solve <br> -4-(2+4(-6)-4-(2^2-5*2))
sweet-ann [11.9K]

Answer:

16

Step-by-step explanation:

This problem requires PEMDAS

Parentheses ( )

Exponents ^

Multiplication

Division

Add

Subtract

Start by solving anything in parentheses. There's an exponent within the parentheses, so we change that 2^2 into 4 and also make sure to multiply 5 x 2 before subtracting.

-4 - (2 + -24 - 4 - (4-10))

-4 - (2 + -24 - 4 - (-6))

Again, solve parentheses first.

-4 - (-22 - 4 - (-6))

-4 - (-26 + 6)

-4 - (-20)

-4 + 20

Answer is 16

4 0
3 years ago
Need to write steps and solve <br> thanks
nalin [4]

<u>Answer:</u>

The coordinates of endpoint V is (7,-27)

<u>Solution:</u>

Given that the midpoint of line segment UV is (5,-11) And U is (3,5).

To find the coordinates of V.

The formula for mid-point of a line segment is as follows,

Midpoint of UV is \frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}

As per the formula,  \frac{x_{1}+x_{2}}{2}=5, \frac{y_{1}+y_{2}}{2}=-11

Here x_{1}=3; y_{1}=5

Substituting the value of x_{1} we get,

\frac{3+x_{2}}{2}=5

3+x_{2}=5\times2

x_{2}=10-3

x_{2}=7

Substituting the value of x_{2} we get,

\frac{5+y_{2}}{2}=-11

5+y_{2}=-11\times2

y_{2}=-22-5

y_{2}=-27

So, the coordinates of V is (7,-27)

7 0
3 years ago
Hoping someone will help me out
pogonyaev

Answer:

It does not converge

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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