Answer: For the sum of 130
First: $90
Second: $40
Step-by-step explanation:
We write equations for each part of this situation.
<u>The Total Charge</u>
Together they charged 1550. This means 1550 is made up of the first mechanics rate for 15 hours and the second's rate for 5 hours. Lets call the first's rate a, so he charges 15a. The second's let's call b. He charges 5b. We add them together 15a+5b=1550.
<u>The Sum of the Rates</u>
Since the first's rate is a and the second is b, we can write a+b=130 since their sum is 130.
We solve for a and b by substituting one equation into another. Solve for the variable. Then substitute the value into the equation to find the other variable.
For a+b=130, rearrange to b=130-a and substitute into 15a+5b=1550.
15a + 5 (130-a)=1550
15a+650-5a=1550
10a+650-650=1550-650
10a=900
a=$90 was charged by the first mechanic.
We substitute to find the second mechanic's rate.
90+b=130
90-90+b=130-90
b= $40 was charged by the second mechanic
x = 3 ; y = 1
Given:
y = -2x + 7
y = 1/3x
Substitute y by its value to find x.
y = y
1/3 x = -2x + 7
x = (-2x + 7) ÷ 1/3
x = (-2x + 7) * 3/1
x = -6x + 21
x + 6x = 21
7x = 21
7x/7 = 21/7
x = 3
Substitute x by its value to solve for y.
y = -2x + 7
y = -2(3) + 7
y = -6 + 7
y = 1
y = 1/3 x
y = 1/3 * 3
y = (1*3)/3
y = 3/3
y = 1
Answer:
Option 2)
Step-by-step explanation:
In a function, any number can be an x-coordinate only once.
Option 1) The 2 appears twice as x.
Option 2) All x-coordinates are different.
Option 3) The 2 appears twice as an x-coordinate.
Option 4) The 3 appears twice as an x-coordinate.
Answer: Option 2)
Answer:
pi will never end just trust me :p
Step-by-step explanation:
QT=16
this is false because i got it right on the test
