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zalisa [80]
3 years ago
12

A man traveled a certain number of miles by automobile and then nine times as far by airplane. His total trip was 600 miles in l

ength. How far did he travel by plane?
Mathematics
1 answer:
Alex17521 [72]3 years ago
4 0
The miles he traveled by plane is nine times greater than the miles traveled by automobile. If the total is 600 miles, then the total distance traveled by automobile would be 60 miles, making the total traveled by airplane 540 miles.
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What do you call a person or an institution who invests the money or the
svetlana [45]

An institutional investor is a person or organization that trades securities in large enough quantities that it qualifies for preferential treatment and lower fees. A retail investor is an individual or non-professional investor who buys and sells securities through brokerage firms or savings accounts.

tip: make sure to reword it

3 0
3 years ago
What reasoning and explanations can be used when solving radical equations and how do extraneous solutions arise from radical eq
Mkey [24]

Answer:

We know that, a 'radical equation' is an equation that contains radical expressions, which further are the expressions containing radicals ( square roots and other roots of numbers ).

In order to solve radical equations, we use the rules of exponents and basic algebraic properties.

The common reasoning to use while solving a radical equation is:

1. Isolate the radical expression.

2. Square both sides of the equation to remove radical.

3. After removing the radical, solve the equation to find the unkown variable

4. Check the answer for the errors occurred by removing the radicals.

For e.g. \sqrt{x}-3=5

i.e. \sqrt{x}-3+3=5+3 ( Adding 3 on both sides )

i.e. \sqrt{x}=8

i.e. (\sqrt{x})^{2} =8^{2}

i.e. x=64.

So, the solution the the radical equation \sqrt{x}-3=5 is x = 64.

Further, we know that an 'extraneous solution' is that root of the radical equation which is not a root of the original equation and is excluded from the domain.

for e.g. Take \sqrt{x+4} =x-2

i.e. (\sqrt{x+4})^{2} =(x-2)^2

i.e. x+4=x^2+4-4x

i.e. 0=x^2-5x

i.e. 0=x(x-5)

i.e. x = 0 and x = 5.

Substituting x = 0 in \sqrt{x+4} =x-2, gives \sqrt{0+4} =0-2 i.e. \sqrt{4} =-2 i.e. 2=-2, which is not possible.

So, x = 0 is a solution that does not satisfy the equation.

Hence, x = 0 is an extraneous solution.

7 0
4 years ago
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ser-zykov [4K]

Answer:

Depends on how wide and tall it is

Step-by-step explanation:

5 0
2 years ago
Car #1 travels 105 miles in 5 hours. Car #2 travels 252 miles in 3
professor190 [17]

Answer:

21 miles/hour

Step-by-step explanation:

Let s= speed of car #1

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s=21 miles/hour

7 0
3 years ago
Show answer in lowest terms. 3 1 /4 - 1 3/16=
SpyIntel [72]
3 - 1 = 2
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answer is : 2 1/16 (in mixed number) or 33/16 (in improper fraction)
4 0
3 years ago
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