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3 years ago

A kite is a rhombus always true sometimes true never true

Mathematics

2 answers:

Lemur [1.5K]3 years ago

4 0

Answer:

sometimes true

Step-by-step explanation:

In general, any quadrilateral with perpendicular diagonals, one of which is a line of symmetry, is a kite. Every rhombus is a kite, and any quadrilateral that is both a kite and parallelogram is a rhombus. EVERY KITE IS NOT A RHOMBUS.

Alexus [3.1K]3 years ago

3 0

Answer: sometimes true

Step-by-step explanation:

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-4 1/2, -5.6, -2 3/8, 2.35 from least to greatest

sweet-ann [11.9K]

Hello!

-2 3/8, -5.6, -4 1/2, 2.35.

Those are ordered from least to greatest!

I really hope you found this helpful! c:

8 0

3 years ago

Which of these sets of ordered pairs would define a line with a positive slope?

Serhud [2]

The correct answer is D

8 0

2 years ago

Question 13

kicyunya [14]

Answer:

The c intercept is 42

The t intercepts are: 6, -1 and 7

Step-by-step explanation:

Given

$c(t) = (t - 6)(t +1)(t-7)$

Solving (a): The c intercept

Simply set t to 0

$c(t) = (t - 6)(t +1)(t-7)$

$c(0) = (0 - 6)(0 +1)(0-7)$

$c(0) = (- 6)(1)(-7)$

$c(0) = 42$

Solving (b): The t intercept

Simply set c(t) to 0

$c(t) = (t - 6)(t +1)(t-7)$

$(t - 6)(t +1)(t-7) = 0$

Split

$t - 6= 0,\ \ t +1= 0,\ \ t-7 = 0$

Solve for t

$t = 6,\ \ t =-1,\ \ t=7$

4 0

3 years ago

This will be so helpful right now thank

RoseWind [281]

Answer:

55 ft.

Step-by-step explanation:

First find the area of Lot X

67 • 70 = 4,690

Subtract the are of Lot X from the total area

8,375 - 4,690 = 3,685

3,685 is the area of Lot Y

Now divide 3,685 by the length of Lot Y : 67

3,685 ÷ 67 = 55

The width of Lot Y is 55 ft.

Hope this helps!

5 0

3 years ago

The average number of traffic tickets issued in a city on any given day

Anton [14]

Answer:

The most tickets were written on Saturday .On Saturday 325 tickets were issued

Step-by-step explanation:

The average number of traffic tickets issued in a city on any given day Sunday-Saturday can be approximated by

$T(x) = -6x^2 + 84x + 37$

Where x represents the number of days after Sunday

T(x) represents the number of traffic tickets issued.

Sunday = x=0

Monday = x=1

Tuesday = x=2

Wednesday = x=3

Thursday = x =4

Friday = x=5

Saturday = x=6

Substitute x= 0

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(0)^2 + 84(0) + 37\\T(x)=37$

On Sunday 37 tickets were issued

Substitute x= 1

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(1)^2 + 84(1) + 37\\T(x)=115$

On Monday 115 tickets were issued

Substitute x= 2

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(2)^2 + 84(2) + 37\\T(x)=181$

On Tuesday 181 tickets were issued

Substitute x= 3

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(3)^2 + 84(3) + 37\\T(x)=235$

On Wednesday 235 tickets were issued

Substitute x= 4

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(4)^2 + 84(4) + 37\\T(x)=277$

On Thursday 277 tickets were issued

Substitute x= 5

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(5)^2 + 84(5) + 37\\T(x)=307$

On Friday 307 tickets were issued

Substitute x= 6

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(6)^2 + 84(6) + 37\\T(x)=325$

On Saturday 325 tickets were issued

Hence the most tickets were written on Saturday .On Saturday 325 tickets were issued

6 0

3 years ago