Help me idk how do do this ;-;
1 answer:
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Answer:
a) the sample size is 400
b) 95% confidence Interval for p is ( 0.0286, 0.0714 )
Step-by-step explanation:
Given the data in the question;
sample size n = 400
x = 20
p = x / n = 20 / 400 = 0.05
q = 1 - p = 1 - 0.05 = 0.95
a)
n = 400
Hence, the sample size is 400
b) 95% confidence Interval for p;
At 95% confidence interval,
significance level ∝ = 1 - 95% = 1 - 0.95 = 0.05
∝/2 = 0.05 / 2 = 0.025
so, Z critical Value ; = 1.96 { from table }
So for Confidence Interval for p;
⇒ p' ± √( p'q' / n )
we substitute
⇒ 0.05 ± 1.96√( (0.05 × 0.95 ) / 400 )
⇒ 0.05 ± 1.96√( 0.00011875 )
⇒ 0.05 ± 1.96 × 0.010897
⇒ 0.05 ± 0.021358
⇒ ( 0.05 - 0.021358 ), ( 0.05 + 0.021358 )
⇒ ( 0.0286, 0.0714 )
Therefore, 95% confidence Interval for p is ( 0.0286, 0.0714 )
<h3>Answer: </h3>
The GCF is 4
The polynomial factors to
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Further explanation:
Ignore the x terms
We're looking for the GCF of 12, 4 and 20
Factor each to their prime factorization. It might help to do a factor tree, but this is optional.
- 12 = 2*2*3
- 4 = 2*2
- 20 = 2*2*5
Each factorization involves "2*2", which means 2*2 = 4 is the GCF here.
We can then factor like so
The distributive property pulls out that common 4. We can verify this by distributing the 4 back in, so we get the original expression back again.
The polynomial inside the parenthesis cannot be factored further. Proof of this can be found by looking at the roots and noticing that they aren't rational numbers (use the quadratic formula).