Complete the proofs .........

Mathematics

1 answer:

yKpoI14uk [10]4 years ago

7 0

Attached the solutions in pic. #2 90, #2 perpendicular lines

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Expand the following (4/5d - 7e)2

tensa zangetsu [6.8K]

Answer: $\dfrac{16d^2}{25}+49e^2-\dfrac{56de}{5}$

Step-by-step explanation:

Given

The expression is

$(\dfrac{4d}{5}-7e)^2$

Use identity $(a-b)^2=a^2+b^2-2ab$

Apply identity

$\Rightarrow \left( \dfrac{4d}{5}-7e\right)^2=\left( \dfrac{4d}{5}\right)^2+(7e)^2-2\times \left( \dfrac{4d}{5}\right)(7e)\\\\\Rightarrow \left( \dfrac{4d}{5}-7e\right)^2=\dfrac{16d^2}{25}+49e^2-\dfrac{56de}{5}$

4 0

3 years ago

Find the midpoint of CH if C has coordinates (-5,-2) and H has coordinates (9,-4)

Sati [7]

Answer:

(2,1)

Step-by-step explanation:

$\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\\\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)\\\\\left(x_1,\:y_1\right)=\left(-5,\:-2\right),\:\left(x_2,\:y_2\right)=\left(9,\:4\right)\\\\=\left(\frac{9-5}{2},\:\frac{4-2}{2}\right)\\\\= (\frac{4}{2} , \frac{2}{2} )\\\\=\left(2,\:1\right)$