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JulsSmile [24]
3 years ago
15

Does a altitude of a triangle divides the triangle into two equal halves??​

Mathematics
1 answer:
trapecia [35]3 years ago
6 0

This only happens if the triangle is isosceles.

Suppose you have triangle ABC, with AB=AC. In this case, the altitude AH bisects both the base BC and the angle BAC, so triangle ABH and ACH are congruent becase they have AH in common, BH=CH and AB=BC because the triangle is isosceles.

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Someone please help me I’ll give out brainliest please dont answer if you don’t know
Nezavi [6.7K]

Answer:

x = 112

Step-by-step explanation:

1/8x + 2 = 16

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1/8x = 14

Multiply both sides by 8

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7 0
2 years ago
NEED HELP ASAP WILL GIVE BRAINLY IF CORRECT
yanalaym [24]

Answer:

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8 0
3 years ago
Read 2 more answers
In triangle STU, UT=5 and angleS=21. Find SU to the nearest tenth
Lubov Fominskaja [6]
<h2>Hello!</h2>

The answer is:

The second option,

SU=13.02=13

<h2>Why?</h2>

We are working with a right triangle, it means that we can use the following trigonometric property:

Tan(\alpha)=\frac{Opposite}{Adjacent}

Which applied to our problem, will be:

Tan(\alpha)=\frac{TU}{SU}

We are given:

m∠S, equal to 21°

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So, substituting and calculating we have:

SU=\frac{TU}{Tan(\alpha)}

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Hence, the answer is the second option

SU=13.02=13

Have a nice day!

5 0
3 years ago
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julia-pushkina [17]

Answer:

10

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3 years ago
What is the measure of the complement of 27 degrees?
serg [7]
The answer is:  " 63° " .
____________________________________________________

Note:  "90 <span>− 27 = 63 " .
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6 0
2 years ago
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