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3 years ago

Does a altitude of a triangle divides the triangle into two equal halves??

Mathematics

1 answer:

trapecia [35]3 years ago

6 0

This only happens if the triangle is isosceles.

Suppose you have triangle ABC, with AB=AC. In this case, the altitude AH bisects both the base BC and the angle BAC, so triangle ABH and ACH are congruent becase they have AH in common, BH=CH and AB=BC because the triangle is isosceles.

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Nezavi [6.7K]

Answer:

x = 112

Step-by-step explanation:

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2 years ago

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yanalaym [24]

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3 years ago

Read 2 more answers

In triangle STU, UT=5 and angleS=21. Find SU to the nearest tenth

Lubov Fominskaja [6]

<h2>Hello!</h2>

The answer is:

The second option,

$SU=13.02=13$

We are working with a right triangle, it means that we can use the following trigonometric property:

$Tan(\alpha)=\frac{Opposite}{Adjacent}$

Which applied to our problem, will be:

$Tan(\alpha)=\frac{TU}{SU}$

We are given:

m∠S, equal to 21°

The side TU (opposite) equal to 5 units.

So, substituting and calculating we have:

$SU=\frac{TU}{Tan(\alpha)}$

$SU=\frac{5units}{Tan(21\°)}$

$SU=13.02=13$

Hence, the answer is the second option

$SU=13.02=13$

Have a nice day!

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3 years ago

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julia-pushkina [17]

Answer:

Step-by-step explanation:

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3 years ago

What is the measure of the complement of 27 degrees?

serg [7]

The answer is: " 63° " .
____________________________________________________

Note: "90 <span>− 27 = 63 " .
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2 years ago

Does a altitude of a triangle divides the triangle into two equal halves??​

Does a altitude of a triangle divides the triangle into two equal halves??