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Alecsey [184]
3 years ago
11

1. Construct a square by using only a compass and straightedge. Explain your steps clearly.

Mathematics
1 answer:
Sedbober [7]3 years ago
7 0
This shows clear step by step to constructing a square.
https://mathbitsnotebook.com/Geometry/Constructions/CCconstructionSquare.html

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What is the solution of the system? Use substitution.
trasher [3.6K]

Hi

4x-y=5

3x-7=2

We need to solve 3x-7=2 for x

Let's start by adding 7 to both sides

3x-7+7=2+7

3x=9

Now just divide both sides by 3 so we can find the value for x

3x/3=9/3

x=3

Now substitute 3 for x in 4x-y=5

4x-y=5

(4)(3)-y=5

-y+12=5

Now add -12

-y=12-12=5-12

-y=-7

Divide both sides by -1 so we can eliminate the negative sign

-y/-1=-7/-1

y=3

The answer is A

(3,7)

I hope that's help:0

6 0
3 years ago
Help me answer the image below
AfilCa [17]

Answer:

8

Step-by-step explanation:

8 0
2 years ago
3. Simplify. *<br> 5m3 + 2m– 7m3 – 8m
Oksanka [162]

Step-by-step explanation:

5m³ + 2m - 7m³ - 8m

= -2m³ -6m

= -2m(m² + 3)

4 0
3 years ago
What is the value of minus 6(-2)cubed - 4 squared - 3(-2x4)?
iogann1982 [59]

Find the value of -6(-2)^2 - 4^2 - 3(-2x^4).

-6(-2)^2 - 4^2 - 3(-2x^4)

Multiply -6(-2)^2.

12^2 - 4^2 - 3(-2x^4)

Subtract 12^2 and -4^2.

8 - 3(-2x^4)

Distribute -3(-2x^4).

8 + 6x^4

Therefore the value of 6(-2)^2 - 4^2 - 3(-2x^4) is 8 + 6x^4.

6 0
3 years ago
Which of the following is a correct equation for the line passing through the point (-2,1) and having slope m= 1/2?
Taya2010 [7]

Incomplete Question the complete Qs is

Which of the following is a correct equation for the line passing through the point (-2,1) and having slope m = 1/2?  

a: y=1/2x+2

b: y=-2x+1/2

c: x-2y=-4

d: y-1=1/2(x+2)

Answer:

The Correct option is c. x-2y=-4

Therefore the correct equation for the line passing through the point (-2,1) and having slope m= 1/2 is

x-2y=-4

Step-by-step explanation:

Given:

Slope = m =\dfrac{1}{2}

point A(x₁, y₁)=(-2,1)  

To Find:  

Equation of Line  =?  

Solution:  

Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,  

i.e equation in point - slope form

(y-y_{1})=m(x-x_{1})

Now on substituting the slope and point A( x₁ , y₁) ≡ ( -2 , 1) we get

(y-1)=\dfrac{1}{2}(x-(-2))\\\\2y-2=x+2\\x-2y=-2-2=-4\\x-2y=-4 As required

Therefore the correct equation for the line passing through the point (-2,1) and having slope m= 1/2 is

x-2y=-4

6 0
2 years ago
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