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Debora [2.8K]
3 years ago
9

A dolphin was swimming 20 feet below the surface of the water. It descended 8 feet to catch a fish. What integer represents its

current depth?
Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
3 0
-28. It’s underwater which is -20 and went -8 more feet down.
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2 + 2<br> please tell me I am clueless
dezoksy [38]

Answer:

22

Step-by-step explanation:

7 0
3 years ago
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On a certain hot​ summer's day, 477 people used the public swimming pool. The daily prices are 1.50 for children and 2.25 for ad
Akimi4 [234]

Answer:

212 children, and 265 adults

Step-by-step explanation:

To find the number of children and adults, we can set up a systems of equations.

x= number of children

y= number of adults

Equation 1: Price

1.50x+2.25y=914.25

Equation 2: Total number of people

x+y=477

Now, let's solve the equation using substitution.

Rearrange the second equation to solve for one variable.

x+y=477

x=477-y

Now plug x equals into the first equation, and solve for y.

1.50x+2.25y=914.25

1.50(477-y)+2.25y=914.25

715.5-1.50y+2.25y=914.25

715.5+0.75y=914.25

0.75y=198.75

y=265

We just solved for the number of adults. Now let's plug y equals into the second equation to find the number of children.

x+y=477

x+265=477

x=212

7 0
2 years ago
Is 2.0 a solution to the equation?<br><br> X-2y=0 , 2x-3y=1
Travka [436]
No, because (2,0) is a coordinate. x=2 and y=0. So just plug in the numbers where there's x or y with the appropriate number, (2 or 0). So in the first equation, x-2y=0, when you pug in the numbers, 2-2(0)=0, you know it's wrong because 2-0=0 isn't correct. So no. the point (2,0) is not a solution to the first equation. Now plug in the numbers for the second coordinate. You get 2(2)-3(0)=1. So 4-0=1. This is once again false no no. (2,0) satisfies neither equations. 
8 0
3 years ago
PLEASE HELP!!! PICKING BRAINLIEST ANSWER!<br>Equation: <img src="https://tex.z-dn.net/?f=2x%5E2%20-2x%20%3D%201" id="TexFormula1
zheka24 [161]

Answer:

I hope it will help you...

5 0
4 years ago
Can someone help me with these math problems please? I need it done by tonight if someone can please help me by then...I'll make
kotegsom [21]

Answer:

For question 3, you would just add 2 to the x values and subtract 2 from the y values, so it would be:

J' (-2, 5)

K' (2, 6)

L' (1, 2)

M' (-3, 1)

For question 4 you would subtract 7 from the x values and 6 from the y values, and that would be:

W' (-6, 1)

X' (-1, -1)

Y' (-3, -6)

Z' (-8, -4)

For question 9 you would end up with:

X' (6, -5)

Y' (7, 1)

Z' (4, 0)

For question 10 you would end up with:

Q' (-1, 2)

R' (1, 7)

S' (-2, 6)

T' (-4, 1)

For question 11 you would end up with:

L' (4, 1)

M' (8, 5)

N' (6, 7)

P' (2, 3)

For question 12 you would end up with:

G' (6, -7)

H' (6, -4)

I' (1, -7)

Hope this is what you were looking for!

 

Step-by-step explanation:


4 0
3 years ago
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