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4 years ago

Can a decimal be an integer or a whole number ?

2 answers:

7 0

It's definately an integer. However, a decimal cannot be a whole number because it needs the value needs to be greater or equal to 1 to become a whole.

WINSTONCH [101]4 years ago

5 0

It can only become a whole number when its over .99 such as 1.00 is a whole number and 7.24 is also a hole get it

You might be interested in

The nth term of a quadratic sequence is an^2 + bn + c.

kupik [55]

Answer:

a = 3, b = -1, c = 2

Step-by-step explanation:

an^2 + bn + c

n = 1:

a + b + c = 4 Eq. 1

n = 2:

4a + 2b + c = 12 Eq. 2

n = 3:

9a + 3b + c = 26 Eq. 3

Eq. 2 minus Eq. 1

3a + b = 8 Eq. 4

Eq. 3 minus Eq. 2

5a + b = 14 Eq. 5

Eq. 5 minus Eq. 4

2a = 6

a = 3

Plug in a = 3 into Eq. 4

3(3) + b = 8

b = -1

Plug in a = 3 and b = -1 into Eq. 1.

3 - 1 + c = 4

c = 2

Answer: a = 3, b = -1, c = 2

3 0

3 years ago

The orbit of the space is approximatly a circle with a radius of 4100 mi. How far do the astronauts travel with each orbit?

Verdich [7]

Answer:

25748 km

Step-by-step explanation:

The distance at which astronauts travel can be obtained by calculating the Circumference of the circle.

Circumference of a circle = 2πr ; π = 3.14

Radius = 4100 km

Circumference of a circle = 2 * 3.14 * 4100

Circumference of the circle = 25748 km

Hence, astronauts travel a distance of 25748 km

7 0

3 years ago

Write an equation of the line passing through the point (5, 1) that is perpendicular to the line 5x+3y=15. An equation of the li

pochemuha

Answer:

$\displaystyle y = \frac{3}{5}\, x + (-2)$ .

Step-by-step explanation:

The slope of a line in a plane would be $m$ if the equation of that line could be written in the slope-intercept form $y = m\, x + b$ for some constant $b$ .

Find the slope of the given line by rearranging its equation into the slope-intercept form.

$3\, y = (-5)\, x + 15$ .

$\displaystyle y = \frac{(-5)}{3} \, x + 5$ .

Thus, the slope of the given line would be $(-5) / 3$ .

Two lines in a plane are perpendicular to one another if and only if the product of their slopes is $(-1)$ .

Let $m_{1}$ and $m_{2}$ denote the slope of the given line and the slope of the line in question, respectively.

Since the two lines are perpendicular to each other, $m_{1}\, m_{2} = (-1)$ . Apply the fact that the slope of the given line is $m_{1} = (-5) / 3$ and solve for $m_{2}$ , the slope of the line in question.

$\begin{aligned}m_{2} &= \frac{(-1)}{m_{1}} \\ &= \frac{(-1)}{(-5) / 3} = \frac{3}{5}\end{aligned}$ .

In other words, the slope of the line perpendicular to $5\, x + 3\, y = 15$ would be $(3 / 5)$ .

If the slope of a line in a plane is $m$ , and that line goes through the point $(x_{0},\, y_{0})$ , the equation of that line in point-slope form would be:

$(y - y_{0}) = m\, (x - x_{0})$ .

Since the slope of the line in question is $(3 / 5)$ and that line goes through the point $(5,\, 1)$ , the equation of that line in point-slope form would be:

$\begin{aligned} (y - 1) = \frac{3}{5}\, (x - 5) \end{aligned}$ .

Rearrange this equation as the question requested:

$\begin{aligned} y - 1 = \frac{3}{5}\, x - 3 \end{aligned}$ .

$\begin{aligned} y = \frac{3}{5}\, x - 2 \end{aligned}$ .

$\begin{aligned} y = \frac{3}{5}\, x + (-2) \end{aligned}$ .

7 0

2 years ago

Find the perimeter of a triangle on a coordinate grid where a(-3,6), B(2,-6) and C(-3,-6)

sleet_krkn [62]

Answer:

Step-by-step explanation: AB = 6-2=4 BC = 3 ( 3- ) = 6 ∙

<h3>Calulate AC find the formula ~ d = ≅ $\sqrt{x} 2-x1) + (x2 - y2) = 3,2 AC = \sqrt[n]{x} (3+3)2 + ( 2 - 6 ) 2 = \sqrt[n]{x} 36 + 16 = \sqrt{} 52 P = 4 + 6 \sqrt{} 52 17.21 to dec. places\\$ </h3>

3 0

4 years ago

Two legs of a right triangle are 4cm, and 3cm. find the length of the hypotenuse of this triangle

sergiy2304 [10]

It'll be 4^2+ 3^2 then the answer you get you take the square root of it which will give you the hypotenuse.
Your answer would be 5 because square root of 25 is 5
If u want the formula it's a^2+b^=c^2
C is the hypotenuse and a and b is the lengths

6 0

4 years ago