The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.
Answer:
The answer is $0.63 per pound of rice.
Step-by-step explanation:
5 ÷ 8 = 0.625
Convert 0.625 to hundredths place
0.625 = 0.63 = $0.63
<span>If the tip, t, varies directly with the number of guests, g, then it means that any change in tip there is a corresponding change in the number of guests. When the tip increases the number of guests increases as well. Therefore,
t </span>α g
To change the it to equal sign, we incorporate a proportionality constant, k.
t =<span> kg
</span>
This equation will represent the relation of t to g.
The answer and work are shown in the picture given.
Answer: Derivative or y = mx + b
Step-by-step explanation:
Take the m value from the standard form equation:
y = mx + b
Or, the second way, is to take the derivative of the function and plug in your x value for your slope.
The derivative of a linear function is very easy to take, so it boils to preference