Answer:
at 2/3 seconds
Step-by-step explanation:
S1(t) = t³ + 2
Average speed, dS1/dt = 3t²
S2(t) = t²
Average speed, dS2/dt = 2t
The distance between the objects is
dS1/dt - dS2/dt
= 3t² - 2t
The time the distance between the two object is at minimum is when the distance is 0
That is, when
3t² - 2t = 0
t(3t - 2) = 0
t = 0 or 3t - 2 = 0
t = 0 or t = 2/3
Answer:
D (i hope)
Step-by-step explanation:
When you minus the highest to the lowest it is added by 10 so
160-140= 20
140-110=30
110-70= 40
70-20= 50
I had added 10 to 160 and got 170
keeping in mind that standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient
Lol u will not believe if i tell u tht my sister have banana phobia... if u show banana to her she will shout loud and if u take it near to her she will cry loud
<span>log (M/N) = log M - log N
so log M - log N = 5
log (P/N) = log P - log N
so log P - log N = 7
If you subtract equation 2 from equation 1, you have log M - log P = -2
That means that log (M/P) = -2 ----> 10^-2 = M/P ---> P = 100M</span>
