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xxTIMURxx [149]
3 years ago
6

Using the lengths​ (in.), chest sizes​ (in.), and weights​ (lb) of bears from a data​ set, the resulting regression equation is

Weightequalsminus274plus0.426 Lengthplus12.1 Chest Size. The​ P-value is 0.000 and the adjusted Rsquared value is 0.925. If an additional predictor variable of neck size​ (in.) is​ included, the​ P-value becomes 0.000 and the adjusted Rsquared becomes 0.933. Why is it better to use values of adjusted Rsquared instead of simply using values of Rsquared​?
Mathematics
1 answer:
galina1969 [7]3 years ago
3 0

Answer:

hello your question lacks the required options here are the options to the question:

a) The unadjusted R^2 decreases or remains the same as more variables are included, but the adjusted R^2 is adjusted for the number of variables and sample size

b) The unadjusted R^2 can only be calculated for regression equations with two or fewer predictor variables while the adjusted R^2 can be calculated for regression equations with any number of predictor variables

c) The unadjusted R^2 increases or remains the same as more variables are included but the unadjusted R^2 is adjusted for the number of variables and sample size

d) The unadjusted R^2 can only be calculated for regression equations with p-values greater than 0 while the adjusted R^2 can be calculated for regression equations with any manner of  p

answer : The unadjusted R^2 increases or remains the same as more variables are included but the unadjusted R^2 is adjusted for the number of variables and sample size ( C )

Step-by-step explanation:

As seen  the unadjusted  R^2 increases anytime a predictor is added to the model even if the predictor has no effect on the model i.e if it is just a chance but the adjusted R^2 has been adjusted for the exact number of predictors in the model and it would increase or decrease based on if the additional predictor added to the model improves the model significantly(more than chance) or if the predictor those not improve the model more than expected

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1410 + 0515 =<br><br> military time <br><br> Good Luck!<br><br> Thank you so much
s2008m [1.1K]

Answer:

1925

Step-by-step explanation:

1410+0515= 1925

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3 years ago
Tiffany types of a page in a page inof an hour. At this rate, how many pages will she type in 3 hours? Express your answer as a
Klio2033 [76]

Answer:

3.0pages

Step-by-step explanation:

If Tiffany type a page in an hour, then;;

1 page = 1 hour

To calculate the number of pages typed in 3 hours, we can express as;

x pages = 3 hours

Divide both expressions

1/x = 1/3

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She will type 3.0pages in 3 hours

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2 years ago
Factor the expression below.
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The answer is C
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3 0
3 years ago
So here's the question
Lesechka [4]
Yes, is subtraction, to get their "difference".

first off, let's convert the mixed fractions, to "improper", and then subtract.

\bf \stackrel{red~yarn}{9\frac{1}{5}}-\stackrel{blue~yarn}{3\frac{11}{25}}

\bf -------------------------------\\\\&#10;\stackrel{mixed}{9\frac{1}{5}}\implies \cfrac{9\cdot 5+1}{5}\implies \stackrel{improper}{\cfrac{46}{5}}&#10;\\\\\\&#10;\stackrel{mixed}{3\frac{11}{25}}\implies \cfrac{3\cdot 25+11}{25}\implies \stackrel{improper}{\cfrac{86}{25}}\\\\&#10;-------------------------------\\\\&#10;\cfrac{46}{5}-\cfrac{86}{25}\impliedby \textit{our LCD is 25}\implies \cfrac{(5\cdot 46)~~-~~(1\cdot 86)}{25}&#10;\\\\\\&#10;\cfrac{230~-~86}{25}\implies \cfrac{144}{25}\implies 5\frac{19}{25}
4 0
3 years ago
CAN SOMEONE PLEASE PLEASE PLEASE HELP ME, YOU’LL GET FREE EASY POINTS IF YOU GIVE ME THE RIGHT ANSWER !!
bekas [8.4K]

Answer:

  1. reflection across BC
  2. the image of a vertex will coincide with its corresponding vertex
  3. SSS: AB≅GB, AC≅GC, BC≅BC.

Step-by-step explanation:

We want to identify a rigid transformation that maps congruent triangles to one-another, to explain the coincidence of corresponding parts, and to identify the theorems that show congruence.

__

<h3>1.</h3>

Triangles GBC and ABC share side BC. Whatever rigid transformation we use will leave segment BC invariant. Translation and rotation do not do that. The only possible transformation that will leave BC invariant is <em>reflection across line BC</em>.

__

<h3>2.</h3>

In part 3, we show ∆GBC ≅ ∆ABC. That means vertices A and G are corresponding vertices. When we map the congruent figures onto each other, <em>corresponding parts are coincident</em>. That is, vertex G' (the image of vertex G) will coincide with vertex A.

__

<h3>3.</h3>

The markings on the figure show the corresponding parts to be ...

  • side AB and side GB
  • side AC and side GC
  • angle ABC and angle GBC
  • angle BAC and angle BGC

And the reflexive property of congruence tells us BC corresponds to itself:

  • side BC and side BC

There are four available congruence theorems applicable to triangles that are not right triangles

  • SSS -- three pairs of corresponding sides
  • SAS -- two corresponding sides and the angle between
  • ASA -- two corresponding angles and the side between
  • AAS -- two corresponding angles and the side not between

We don't know which of these are in your notes, but we do know that all of them can be used. AAS can be used with two different sides. SAS can be used with two different angles.

SSS

  Corresponding sides are listed above. Here, we list them again:

  AB and GB; AC and GC; BC and BC

SAS

  One use is with AB, BC, and angle ABC corresponding to GB, BC, and angle GBC.

  Another use is with BA, AC, and angle BAC corresponding to BG, GC, and angle BGC.

ASA

  Angles CAB and CBA, side AB corresponding to angles CGB and CBG, side GB.

AAS

  One use is with angles CBA and CAB, side CB corresponding to angles CBG and CGB, side CB.

  Another use is with angles CBA and CAB, side CA corresponding to angles CBG and CGB, side CG.

3 0
1 year ago
Read 2 more answers
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