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drek231 [11]
3 years ago
6

4,444,444 the digit in the hundreds thousands place is 10 times the value of the digit in the ten thousands place?

Mathematics
1 answer:
Stolb23 [73]3 years ago
7 0
If this question is:
"true or false:
the digit in the hundreds thousands place is 10times the value of the digit in the ten thousands place"
then that would be true.
I'm not really sure what you're asking... sorry :|
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Where is the point (0, -5) located on the coordinate plane?
Anna007 [38]
On the y-axis.

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3 0
3 years ago
The edge of a cube was found to be 30 cm with a possible error in measurement of 0.5 cm. Use differentials to estimate the maxim
IgorLugansk [536]

Answer:

for the volume a cube

Possible error = 1350cm³

Relative error = 0.05

Percentage error = 5%

For the surface area of a cube

Possible error = 180cm²

Relative error = 0.0333

Percentage error = 3.33%

Step-by-step explanation:

A cube is a three dimensional solid object with six (6) faces, twelve (12) edges and eight(8) vertices.

The volume of a cube = x³

Where x= length of the edge of a cube

X = 30cm 0.5cm

Differentiate V with respect to x (V = Volume of a cube)

dV/dx= 3 x²

dV= 3 x² . dx

dV = 3 × 30² × (0.5)

dV= 2700(0.5)

= 1350cm³

Maximum possible error = 1350cm³

Relative error = possible error /Volume

= dV/V

Recall that V = x³

V= (30)³

A = 27000cm³

Substitute the values for and V into the formula for Relative error

Relative error = 1350/27000

Relative error = 0.05

% error = Relative error × 100

= 0.05× 100

= 5%

Surface Area of a cube = 6x²

A = 6x²

Differentiate A with respect to x

dA/dx = 12x

dA/dx = 12x . dx

= 12 × 30 (0.5)

= 180cm²

Maximum possible error = 180cm²

Relative error = possible error / surface area

= dA/A

Recall that A = 6x²

A = 6(30)²

A = 5400cm²

Substitute the values for and A into the formula for Relative error

Relative error = 180/5400

Relative error = 0.0333(4 decimal place)

% error = Relative error × 100

= 0.0333 × 100

= 3.33%

8 0
3 years ago
8-(-4)+33÷(-3) what is the answer
mixas84 [53]

Answer:

Hiiiiiiiiiiiii

The answer is 1

5 0
2 years ago
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In a hydraulic jack, the pipe below the load has an area of 5 m2, and the pipe through which the input force transmits has an ar
anzhelika [568]

Answer:

0.2kN

Step-by-step explanation:

An hydraulic jack works by the principle that pressure applied to one part in an enclosed liquid is transmitted equally in all parts of the liquid. this is in accordance with Pascal's principle.

Pressure= Force/Area

P=F/A

Pressure due to the load= Pressure due to input force for the system to be in balance.

Let force due to load be F₁, input force be F₂, Area at the load piston be A₁ and the area of the pipe through which the input force transmits be A₂, then,

F₁/A₁=F₂/A₂

10000N/5m²=F₂/1m²

F₂=(1000N×1m²)/5m²

F₂=200N

=0.2kN

6 0
3 years ago
5+2f;f=6.1 how do you do it im so confused
liberstina [14]
F is the variable. since f is equal to 6.1 you can plug it into the other equation. you multiply 2 and 6.1. this equals 12.2 then you add two. the final answer is 14.2
7 0
3 years ago
Read 2 more answers
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