Given that f(x)=x^2-4x -3 and g(x)=x+3/4 solve for f(g(x)) when x=9
1 answer:
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Answer:
The equation of the ellipse is
Step-by-step explanation:
The standard form of the equation of an ellipse with center (0 , 0) is
, where
- The coordinates of the vertices are (± a , 0)
- The coordinates of the foci are (± c , 0) , where c ² = a² - b²
∵ The ellipse is centered at the origin
∴ The center of it is (0 , 0)
∵ It has foci at (± 8 , 0)
- The coordinates of the foci are (± c , 0)
∴ c = ±8
∵ It has Vertices at (± 17 , 0)
- The coordinates of the vertices are (± a , 0)
∴ a = ±17
∵ c² = a² - b²
- Substitute the values of c and a to find b
∴ (8)² = (17)² - b²
∴ 64 = 289 - b²
- Add b² to both sides
∴ b² + 64 = 289
- Subtract 64 from both sides
∴ b² = 225
- Take √ for both sides
∴ b = ± 15
∵ The equation of the ellipse is
- Substitute the values of a and b in it
∴ ⇒
∴ The equation of the ellipse is
Answer:
see explanation
Step-by-step explanation:
sum the parts of the ratio, 2 + 1 = 3 parts , thus
81 cm² ÷ 3 = 27 cm² ← value of 1 part of the ratio
2 parts = 2 × 27 = 54 cm²
Area of A = 54 cm² and area of B = 27 cm²
The side of the original square = = 9 cm
The width of both rectangles is 9 cm ( width remains unchanged after cut )
Thus
Rectangle A
9 × length = 54 ( divide both sides by 9 )
length = 6 cm
Rectangle B
9 × length = 27 ( divide both sides by 9 )
length = 3 cm
Rectangle A → length = 6 cm, width = 9 cm
Rectangle B → length = 3 cm , width = 9 cm