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2 years ago

Use properties of operations to write an equivalent expression by combining like terms.

Mathematics

2 answers:

bearhunter [10]2 years ago

8 0

Answer:

16+4p mark brainliest its correct

Step-by-step explanation:

Radda [10]2 years ago

5 0

Answer:

Subtract

9p from 13p.

16+4p

Step-by-step explanation:

You might be interested in

1) x+30 = 40

soldier1979 [14.2K]

1)x+30=40

x=40-30

Answer :x=10

2)30-20+2x=10

10+2x=10

2x=0

Answer: x=0

3)3x-10+13=-2x+28

3x+3=-2x+28

3x+2x+3=28

3x+2x=28-3

5x=28-3

5x=25

x=5

4)13x-23-45=-7x+12

13x-68=-7x+12

13x+7x-68=12

13x+7x=12+68

20x=12+68

20x=80

x=4

5)2(x+4)=10x+24

2x+8=10x+24

2x-10x+8=24

2x-10x=24-8

-8x=24-8

-8x=16

x=-2

6)3(x-5)=1-(2x-4)

3x-15=1-(2x-4)

3x-15=1-2x+4

3x-15=5-2x

3x+2x-15=5

3x+2x=5+15

5x=5+15

5x=20

x=4

7)5x-10=15

5x=15+10

5x=25

x=5

8)x+4=x+6

4=6

no solution

PLEASE MARK ME AS BRAINLIEST

4 0

3 years ago

(1/1+sintheta)=sec^2theta-secthetatantheta pls help me verify this

Xelga [282]

Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

$\displaystyle \frac{1}{1+\sin\theta} = \sec^2\theta - \sec\theta \tan\theta$

To start, we can multiply the fraction by (1 - sin(θ)). This yields:

$\displaystyle \frac{1}{1+\sin\theta}\left(\frac{1-\sin\theta}{1-\sin\theta}\right) = \sec^2\theta - \sec\theta \tan\theta$

Simplify. The denominator uses the difference of two squares pattern:

$\displaystyle \frac{1-\sin\theta}{\underbrace{1-\sin^2\theta}_{(a+b)(a-b)=a^2-b^2}} = \sec^2\theta - \sec\theta \tan\theta$

Recall that sin²(θ) + cos²(θ) = 1. Hence, cos²(θ) = 1 - sin²(θ). Substitute:

$\displaystyle \displaystyle \frac{1-\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta \tan\theta$

Split into two separate fractions:

$\displaystyle \frac{1}{\cos^2\theta} -\frac{\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta\tan\theta$

Rewrite the two fractions:

$\displaystyle \left(\frac{1}{\cos\theta}\right)^2-\frac{\sin\theta}{\cos\theta}\cdot \frac{1}{\cos\theta}=\sec^2\theta - \sec\theta \tan\theta$

By definition, 1 / cos(θ) = sec(θ) and sin(θ)/cos(θ) = tan(θ). Hence:

$\displaystyle \sec^2\theta - \sec\theta\tan\theta \stackrel{\checkmark}{=} \sec^2\theta - \sec\theta\tan\theta$

Hence verified.

8 0

2 years ago

match each binomial expression with the set of coefficient of the term obtain by expanding the expression

mars1129 [50]

$(2x+y)^3$ = $8x^3+12x^2y+6xy^2+y^3$

The coefficients are 8 , 12, 6, 1

$(2x+3y)^4$ = $16x^4+96x^3y+216x^2y^2+216xy^3+81y^4$

The coefficients are 16, 96, 216, 216, 81

$(3x+2y)^3$ = $27x^3+54x^2y+36xy^2+8y^3$

The coefficients are 27, 54,36 , 8

$(x+y)^4$ = x^4+4x^3y+6x^2y^2+4xy^3+y^4

The coefficients are 1, 4, 6, 4, 1

8 0

3 years ago

Read 2 more answers

Find the point of depression from point A to point C

lesya [120]

The angle of depression equals 32.

A way that you can solve this is by finding angle c. Angle C would be the same as the angle of depression because of alternate angles being congruent.

So you do the triangle angle sum theorem.

58+90+x=180

Simplify

148 +x=180

Subtract 148 from both sides

x=32

So Since angle c equals to 32 degrees, then the angle of depression is also 32 degrees.

3 0

3 years ago

Trisha had the following seven distances (in feet) in the triple jump.

butalik [34]

The range of a data set is the greatest value minus the smallest value.

The greatest value here is 32, and the smallest value is 27:

$\sf Range=32-27=\boxed{\sf 5}$

5 0

3 years ago