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Alona [7]
4 years ago
5

Determine whether the improper integral converges or diverges, and find the value of each that converges.

Mathematics
1 answer:
pantera1 [17]4 years ago
7 0

Answer:

It diverges.

Step-by-step explanation:

We are given the integral: \int\limits^{-1}_{-\infty} \ln |x| dx

\int\limits^{-1}_{-\infty} \ln |x| dx=\int\limits^{-1}_{-\infty} \ln (-x) dx=\\\\= \lim_{t \to \infty} \int\limits^{-1}_{-t} \ln (-x) dx= \lim_{t \to \infty}( x(\ln \left(-x\right)-1))|^{-1}_{-t}=1-\infty=-\infty

So it is divergent.

You might be interested in
Raymond drove from San Antonio to Dallas in 5.2 Hours. It is 390miles from San Antonio to Dallas. If Raymond drove at a constant
Aleonysh [2.5K]

Answer:

75mph                                  

calculated it                       

3 0
3 years ago
Read 2 more answers
If EG = 59, and EF = 8x - 14, while FG = 4x + 1
lyudmila [28]

Answer:

x = 6

Step-by-step explanation:

EG = 59

EF = 8x - 14

FG = 4x + 1

to find the value of x

EF + FG = EG (same line)

8x - 14 + 4x + 1 = 59

12x -13 = 59

12x = 59 + 13

12x = 72

x = 72 ÷ 12

x = 6

You can even cross check for correct answer

EF + FG = EG

instead of x place the x's value we got

8x - 14 + 4x + 1 = 59

8 (6) - 14 + 4 (6) + 1 = 59

48 - 14 + 24 + 1 = 59

34 + 25 = 59

59 = 59

CROSS - CHECKED

4 0
3 years ago
Which of the following functions I which of the following functions are one to one? Select all that apply there are 3 answers
ivann1987 [24]

Answer:

The function f(x)=\frac{x-1}{3x+3} is one-to-one function ⇒ 1st

The function f(x)=\sqrt{5x+9} is one-to-one function ⇒ 2nd

The function f(x)=\frac{1}{2}x^{3} is one-to-one function ⇒ 4th

Step-by-step explanation:

* Lets explain how to solve this problem

- One to one function is the function that has no reputation in the value

 of the y-coordinates for every corresponding x-coordinates

- That means when you draw a horizontal line at any value of y, then

  the horizontal line intersects the graph of the function at one point

  only

- So to solve the problem look to the attached figures

# The red graph of the function f(x)=\frac{x-1}{3x+3} ⇒1st graph

- In this graph if we draw a horizontal line at any value of y it will

 intersect the graph at only one point

- Take care there is a horizontal asymptote at y= 1/3, that means

  there is no value of x at y = 1/3

∴ The function f(x)=\frac{x-1}{3x+3} is one-to-one function

# The blue graph of the function f(x)=\sqrt{5x+9} ⇒2nd graph

- In this graph if we draw a horizontal line at any value of y it will

 intersect the graph at only one point

∴ The function f(x)=\sqrt{5x+9} is one-to-one function

# The green graph of the function f(x)=\frac{1}{2}x^{3} ⇒3rd graph

- In this graph if we draw a horizontal line at any value of y it will

 intersect the graph at only one point

∴ The function f(x)=\frac{1}{2}x^{3} is one-to-one function

# The purple graph of the function f(x)=\frac{7}{4x^{2}} ⇒5th graph

- In this graph if we draw a horizontal line at any value of y it will

 intersect the graph at more than one point

∴ The function f(x)=\frac{7}{4x^{2}} is not one-to-one function

# The black graph of the function f(x)=3x^{4}+7x^{3} ⇒4th graph

- In this graph if we draw a horizontal line at any value of y it will

 intersect the graph at more than one point

∴ The function f(x)=3x^{4}+7x^{3} is not one-to-one function

* The answers are 1st , 2nd and 4th functions

8 0
3 years ago
Round off 547,237 to the nearest hundred thousand
vekshin1

Answer:

500,000

Step-by-step explanation:


3 0
3 years ago
Fine the value of x.
aliina [53]
  • <em>Answer:</em>

<em>x = 20</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there ! </em>

<em>we have </em><u><em>opposite angles</em></u><em> =></em>

<em>2 + 3x = 62</em>

<em>3x = 62 - 2</em>

<em>3x = 60</em>

<em>x = 60 : 3</em>

<em>x = 20</em>

<em>Good luck !</em>

6 0
4 years ago
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