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Free_Kalibri [48]
2 years ago
7

Christian purchased a new car. The value of the car is depreciating at a

Mathematics
1 answer:
LenKa [72]2 years ago
3 0

18000 represents the price of the new car.

The value of the car in 6 years can be found by substituting 6 for the variable t, as follows:

V = 18000(1-.12)^6\\V = 18000(0.4644)\\

In 6 years, it will be worth around $8359.27.

The equation for the car worth $20000 is this:

V = 20000(1-.15)^6\\V = 20000(0.3771)\\

In 6 years, the other car will be worth $7542.99, so the car worth $18000 will have more value in 6 years.

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G(-5) = -1/4(-5) - 1 = 0.25;
G(-2) = -1/4(-2) - 1 = -0.25;
G(-1) = -1/4(-1) - 1 = -0.75;
///////////////////////////////////

////For G(x) = (x-1)^2 - 3////
G(-1) = ((-1) -1)^2 - 3 = 1;
G(-2) = ((-2) - 1)^2 - 3 = 6;
G(-5) = ((-5) - 1)^2 - 3 = 33;
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////For G(x) = 1/4x + 2////////
G(-5) = 1/4(-5) + 2 = 0.75;
G(-2) = 1/4(-2) + 2 = 1.5;
G(-1) = 1/4(-1) + 2 = 1.75;

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