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Stels [109]
3 years ago
13

I need help solving these problem 14=8-6r

Mathematics
2 answers:
daser333 [38]3 years ago
8 0
14 = 8 -6r
Reorder so the common terms are on one side.
Subtract 8 from both sides.
8 -6r = 14 --> -6r = -8 +14
-6r = 6
Divide each term by -6 and simplify.

r = -1

Margaret [11]3 years ago
4 0
8 - 6r = 14
Subtract 8 from both sides. ( I'm sure you learned this )
6r = 6
r = 1
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NEED HELP ASAP
iogann1982 [59]

Answer:

[x + 2][x + 5][x - 1]

Step-by-step explanation:

The Leading Coefficient is 1 and the initial value is 10; they have a common factor of 1, so that automatically gives us our first factor of [x - 1]. Now, since the divisor\factor is in the form of x - c, use what is called Synthetic Division. Remember, in this formula, -c gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:

1| 1 6 3 −10

↓ 1 7 10

__________

1 7 10 0 → {x}^{2} + 7x + 10 >> [x + 2][x + 5]

You start by placing the <em>c</em> in the top left corner, then list all the coefficients of your dividend [x³ + 6x² + 3x - 10]. You bring down the original term closest to <em>c</em> then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an x², the 7x follows right behind it, then 10, giving you the other factor of {x}^{2} + 7x + 10, which can be factored further to [x + 2][x + 5], attaching this to the first factor you started out your work on:

[x + 2][x + 5][x - 1]

I am joyous to assist you anytime.

3 0
3 years ago
Need to find a and b
svp [43]
First, 126/32 so divide top and bottom by 2

126 / 2 = 63
32/2 = 16

answer
 
a = 16
and
b = 2


5 0
3 years ago
A fair coin is tossed 5000 times. What can you say about getting the outcome of exactly 2500 tails
WINSTONCH [101]

Step-by-step explanation:

You can't expect to get exactly 2500 out of 5000 tosses more than a few times . You will come pretty close, but that's only good in horseshoes.

Of course I'm answering this on the basis of a computer language and not actually performinig this a million tmes, each part of a million consisting of 5000 tosses.

Simulations and not completely unbiased, but based on experience, 5000 is a very small number and getting 2500 more than a couple of times is unlikely

6 0
3 years ago
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The constant proportionality is whats left over
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Look at the two expressions.<br><br>3x−18<br><br>3⋅(x−6)<br><br>Are the two expressions equivalent?
Ivanshal [37]
Yes because if you distribute the 3 and multiply it with 3 • x and 3• 6 you’ll get 3x-18
8 0
3 years ago
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