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3 years ago

I need help solving these problem 14=8-6r

2 answers:

8 0

14 = 8 -6r
Reorder so the common terms are on one side.
Subtract 8 from both sides.
8 -6r = 14 --> -6r = -8 +14
-6r = 6
Divide each term by -6 and simplify.

r = -1

Margaret [11]3 years ago

4 0

8 - 6r = 14
Subtract 8 from both sides. ( I'm sure you learned this )
6r = 6
r = 1

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Read 2 more answers

A The length of a rectangle is 4 m more

Lady bird [3.3K]

Given :

The length of a rectangle is 4m more than the width.
The area of the rectangle is 45m²

⠀

To Find :

The length and width of the rectangle.

⠀

Solution :

We know that,

$\qquad { \pmb{ \bf{Length \times Width = Area_{(rectangle)}}}}\:$

So,

Let's assume the length of the rectangle as x and the width will be (x – 4).

⠀

Now, Substituting the given values in the formula :

$\qquad \sf \: { \dashrightarrow x \times (x - 4) = 45 }$

$\qquad \sf \: { \dashrightarrow {x}^{2} - 4x = 45 }$

$\qquad \sf \: { \dashrightarrow {x}^{2} - 4x - 45 = 0 }$

$\qquad \sf \: { \dashrightarrow {x}^{2} - 9x+ 5 x - 45 = 0 }$

$\qquad \sf \: { \dashrightarrow x(x - 9) + 5(x - 9) = 0 }$

$\qquad \sf \: { \dashrightarrow (x - 9) (x + 5) = 0 }$

$\qquad \sf \: { \dashrightarrow x = 9, \: \: x = - 5}$

⠀

Since, The length can't be negative, so the length will be 9 which is positive.

⠀

$\qquad { \pmb{ \bf{ Length _{(rectangle)} = 9\:m}}}\:$

$\qquad { \pmb{ \bf{ Width _{(rectangle)} = 9 - 4=5\: m}}}\:$

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1 year ago