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aleksley [76]
3 years ago
13

Rewrite as a log: y=7^x

Mathematics
2 answers:
FromTheMoon [43]3 years ago
8 0

Answer:

log7(y)=x

Step-by-step explanation:

Hatshy [7]3 years ago
5 0
Maybe would help mathwath
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Iana started to evaluate the function f(x) = 2x2 – 3x + 7 for the input value 2.
Sati [7]
The answer is nine because 2(4)=8   3(2)=6   7=7, os 8-6+7= 2+7 =9
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PLEASE HELP. WILL GIVE BRAINLIEST!!!!!!!!!
Alex777 [14]

Answer:

A

Step-by-step explanation:

7 0
3 years ago
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Given that 4x:3 = 11:7 calculate x
Pani-rosa [81]

Answer: The answer is 33/28 or 1.17

If it's rounded it will be 1.18

Step-by-step explanation:

7 0
3 years ago
The number of printers sold since 2003 at Mike’s office supply store can be modeled by the function N(t) = 15t + 85 and the pric
fiasKO [112]

Answer:

The total amount of revenue is $82950

Step-by-step explanation:

* Lets explain how to solve the problem

- The number of printers sold since 2003 at Mike’s office supply store

 can be modeled by the function N(t) = 15t + 85

∴ The number of printers is N(t) = 15t + 85

- The price per printer can be modeled by P(t) = 15t² - 32t + 126

∴ The price per printer is P(t) = 15t² - 32t + 126

- t is the number of years since 2003

- The amount of revenue is the product of the number of printers

  sold and the price per printer

∴ Revenue = N(t) × P(t)

- We need to find the total amount of revenue generated by the

 sales of printers in the office supply store in 2009

∵ t is the number of years since 2003

∴ In 2009 t = 2009 - 2003 = 6 years

∵ t = 6 years

∵ N(t) = 15t + 85

∴ N(6) = 15(6) + 85 = 175

∴ They sold 175 printers from 2003 to 2009

∵ t = 6 years

∵ P(t) = 15t² - 32t + 126

∴ P(6) = 15(6)² - 32(6) + 126 = 474

∴ The price per printer is $474

∵ Revenue = N(t) × P(t)

∴ Revenue = 175 × 474 = 82950

* The total amount of revenue is $82950

3 0
4 years ago
Shannon rolls 2 fair dice and adds the results from each. Work out the probability of getting a total of 13.
Bingel [31]

Answer:

0.

Step-by-step explanation:

Fair dice are dice that have 6 sides, and the probability of rolling a side is the same as rolling another.

Since each die has 6 sides, the most you can get from the two dice are 6 + 6 = 12. Therefore, getting a 13 is impossible. So, there is a probability of 0.

Hope this helps!

4 0
3 years ago
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