Answer:
The integers are 4 and 7 or -2 and 1.
Step-by-step explanation:
You can make a system of equations with the description of the two integers.
1. x = y + 3
2. 2x + 2 = y^2
The simplest and the fastest way to solve this system in this case is substitution. You can substitute x for y + 3 in the second equation.
1. x = y + 3
2. 2(y + 3) + 2 = y^2
Now simplify and solve the second one. For convenience, I will just disregard the first equation for now.
2y + 6 + 2 = y^2
y^2 - 2y - 8 = 0
You can factor this equation to solve for y.
(y - 4) (y + 2) = 0
y = 4, y = -2
Now we can substitute the value of y for x in the first equation.
x = 7, x = 1
Answer:
2 is the required answer.
Step-by-step explanation:
<u>Solution:</u>
<u>Given</u><u>:</u>
-5x+3y=2..............(i)
Putting the value of y=2x in the equation (i); we get:
i.e -5x+3×2x=2
or, -5x+6x=2
or, x=2
i.e. x=2
y=2x=2×2=4
1: 0.8
2: 0.4
3: 0.1
4: 0.7
Have a good day and ask questions!!
-Kaylie
Answer:
It's 1/2*DB*AC
Step-by-step explanation:
Part A Simplify:
Answer is - 12b + 6c + 18
Part B
Answer is (D)
Factor/simplify
- 12b + 6c + 18
6(- 2b + c + 3)
= (6)(- 2b + c + 3)
= (6)(- 2b ) + (6)(c) + (6)(3)
= - 12b + 6c + 18
therefore,- 12b + 6c + 18; Factored in GCF is 6(-2b + c + 3)
- 12b + 6c + 18
reorder the terms
18 + 12b + 6c
Factor out the GCF " 6"
6(3 + 2b + c)
Final Result:
6(3 + 2b + c)
Hope this helps
