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Reika [66]
3 years ago
13

Enter T or F depending on whether the statement is a true proposition or not. (You must enter T or F -- True and False will not

work.) F 1. 290 is divisible by 17 T2. 360 divides 20 F3. 16 divides 208 F4. 10∣181 F5. 17 divides 171 F6. 176∣16 F7. 33653 is divisible by 188 F8. 17878 is divisible by 177 F9. 13∣221
Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
6 0

Answer:

(1) F          (5) F            (9) T

(2) F          (6) F

(3) T          (7) F

(4) F          (8) F

Step-by-step explanation:

(1)

290 is divisible by 17.

\frac{290}{17}=(17\times17)+1

On dividing 290 by 17 there is a remainder left, i.e. 1.

Thus, this statement is False, F.

(2)

360 divides 20.

\frac{20}{360}=\frac{1}{18}

On dividing 20 by 360 the result are in fractions.

Thus, this statement is False, F.

(3)

16 divides 208.

\frac{208}{16}=(13\times16)+0

On dividing 208 by 16 there is no remainder left.

Thus, this statement is True, T.

(4)

10 | 181

\frac{181}{10}= (18\times10)+1

On dividing 181 by 10 there is a remainder left, i.e. 1.

Thus, this statement is False, F.

(5)

17 divides 171

\frac{171}{17} =(17\times10)+1

On dividing 171 by 17 there is a remainder left, i.e. 1.

Thus, this statement is False, F.

(6)

176 | 16

\frac{16}{176}= \frac{1}{11}

On dividing 16 by 176 the result are in fractions.

Thus, this statement is False, F.

(7)

33653 is divisible by 188

\frac{33653}{188} =(179\times188)+1

On dividing 33653 by 188 there is a remainder left, i.e. 1.

Thus, this statement is False, F.

(8)

17878 is divisible by 177

\frac{17878}{177} =(101\times177)+1

On dividing 17878 by 177 there is a remainder left, i.e. 1.

Thus, this statement is False, F.

(9)

13 | 221

\frac{221}{13}= (17\times13)+0

On dividing 221 by 13 there is no remainder left.

Thus, this statement is True, T.

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mario62 [17]

Answer:

24 Combinations Total

Step-by-step explanation:

METHOD 1 (no advanced math skills needed)

i. Number the friends: a, b, c, and d

ii. List all possible combinations...

  1. a b c d
  2. a b d c
  3. a c b d
  4. a c d b
  5. a d b c
  6. <u>a d c b</u>
  7. b a c d
  8. b a d c
  9. b c a d
  10. b c d a
  11. b d a c
  12. <u>b d c a</u>
  13. c a b d
  14. c a d b
  15. c b a d
  16. c b d a
  17. c d a b
  18. <u>c d b a</u>
  19. d a b c
  20. d a c b
  21. d b a c
  22. d b c a
  23. d c a b
  24. <u>d c b a</u>

To speed up the process instead of sitting here and listing 24 combinations, after two sections you can see that with friend "a" sitting all the way at the left there are six combinations and the same goes for friend "b". You can then multiply 6 (number of combinations with that friend <em>first</em>) and 4 (friends) to get 24.

METHOD 2

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3 years ago
How would you solve this equation? Please show steps
Serhud [2]
Simple....

you have: 3x= \sqrt{12-12x}

So...first you know you're trying to find x..

But, you have a square root on one side...to remove this you'd have to square both sides--->>>

(3x)^{2} = \sqrt{12-12x}  ^{2}

Leaving you with....

9x^{2} =12-12x

Move the terms over and set it equal to zero.

-->>

9x^{2}+12x-12=0

Factor out a 3...

3( 3x^{2} +4x-4=0)

What multiplies to -12 and adds to 4?

6*-2=-12

6+-2=4

Leaving you with...

3(3x-2)(x+2)=0

Remember you're solving for 0....

3x-2=0

3x-2=0
    +2  +2

3x=2

\frac{3x}{3} = \frac{2}{3}

x=
\frac{2}{3}

Then-->>

x+2=0

x+2=0
  -2   -2

x=-2

Thus, your answer.
 


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