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Reika [66]
3 years ago
13

Enter T or F depending on whether the statement is a true proposition or not. (You must enter T or F -- True and False will not

work.) F 1. 290 is divisible by 17 T2. 360 divides 20 F3. 16 divides 208 F4. 10∣181 F5. 17 divides 171 F6. 176∣16 F7. 33653 is divisible by 188 F8. 17878 is divisible by 177 F9. 13∣221
Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
6 0

Answer:

(1) F          (5) F            (9) T

(2) F          (6) F

(3) T          (7) F

(4) F          (8) F

Step-by-step explanation:

(1)

290 is divisible by 17.

\frac{290}{17}=(17\times17)+1

On dividing 290 by 17 there is a remainder left, i.e. 1.

Thus, this statement is False, F.

(2)

360 divides 20.

\frac{20}{360}=\frac{1}{18}

On dividing 20 by 360 the result are in fractions.

Thus, this statement is False, F.

(3)

16 divides 208.

\frac{208}{16}=(13\times16)+0

On dividing 208 by 16 there is no remainder left.

Thus, this statement is True, T.

(4)

10 | 181

\frac{181}{10}= (18\times10)+1

On dividing 181 by 10 there is a remainder left, i.e. 1.

Thus, this statement is False, F.

(5)

17 divides 171

\frac{171}{17} =(17\times10)+1

On dividing 171 by 17 there is a remainder left, i.e. 1.

Thus, this statement is False, F.

(6)

176 | 16

\frac{16}{176}= \frac{1}{11}

On dividing 16 by 176 the result are in fractions.

Thus, this statement is False, F.

(7)

33653 is divisible by 188

\frac{33653}{188} =(179\times188)+1

On dividing 33653 by 188 there is a remainder left, i.e. 1.

Thus, this statement is False, F.

(8)

17878 is divisible by 177

\frac{17878}{177} =(101\times177)+1

On dividing 17878 by 177 there is a remainder left, i.e. 1.

Thus, this statement is False, F.

(9)

13 | 221

\frac{221}{13}= (17\times13)+0

On dividing 221 by 13 there is no remainder left.

Thus, this statement is True, T.

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Which shows the correct substitution of the values a, b, and c from the equation –2 = –x + x2 – 4 into the quadratic formula?
dimaraw [331]

Answer:

We substitute x=\frac{-(-1)+/-\sqrt{(-1)^2-4(1)(-2)} }{2(1)}

And simplify x=\frac{1+/-\sqrt{1-4(1)(-2)} }{2}

Step-by-step explanation:

First we rearrange the equation -2=-x+x2-4 into standard form of a quadratic ax^2+bx+c=0. This equation becomes x^2-x-2=0 where a=1, b=-1, and c=-2.

The formula is:

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}.

We substitute x=\frac{-(-1)+/-\sqrt{(-1)^2-4(1)(-2)} }{2(1)}

And simplify x=\frac{1+/-\sqrt{1-4(1)(-2)} }{2}

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8 0
3 years ago
A company can sell 2000 magazine subscriptions at $40 each. For each $5 increase in the price, it will sell 200 fewer subscripti
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Let x denote the number of times at which price is increased by $5 for each magazine.
{Write an expression for the total revenue of company}
Let y denote the total revenue of the company,
y = (2000 - 200x) × ($40 + $5x)
{200x is the number of subscriptions being lost due to the price increases}
{$5x is the amount of increase in price of each magazine}

y = 2000($40) + 2000($5x) - 200x($40) - 200x($5x)
y = $80,000 + $10,000x - $8000x - $1000x^2
y = $80,000 + $18'000x - $1000x^2
{Since the coefficient of x^2 is (-1000), this graph is a sad face curve. This means the only stationary point on the curve is a maximum point}
{Differentiate y in terms of x}
dy/dx = $18,000 - $2000x
{dy/dx = 0 at stationary point, or when gradient = 0}
dy/dx = 0
$18,000 - $2000x = 0
$2000x = $18,000
x = 9 {dollar signs cancel out when they are divided}

Subscription price to attain maximum revenue should be: $40 + (9 × $5) = $95

Hope this helps!
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