All categories

3 years ago

1. The parallel line needs to intersect the other two sides at their

Mathematics

1 answer:

mrs_skeptik [129]3 years ago

4 0

Yes, that like will divide the side in proportion

You might be interested in

Solve the quadratic equation for x in the simplest equation -6x^2+15x+9=0

-BARSIC- [3]

Answer:

Step-by-step explanation:

-6x²+15x+9=0

divide by -3

2x²-5x-3=0

2x²+x-6x-3=0

x(2x+1)-3(2x+1)=0

(2x+1)(x-3)=0

either x=-1/2

or x=3

8 0

2 years ago

Solve by any method (graphing, substitution, linear combination) <br> y=x−7 <br> 5x+2y=7

Virty [35]

Answer:

(x, y) = (3, -4)

Step-by-step explanation:

See the attached for a graph.

3 0

3 years ago

Use the given values of n and p to find the minimum usual value μ−2σ and the maximum usual value μ+2σ. Round to the nearest hund

lbvjy [14]

Answer:

μ−2σ = 1,089.26

μ+2σ = 1,097.62

Step-by-step explanation:

The standard deviation of a sample of size 'n' and proportion 'p' is:

$\sigma=\sqrt{\frac{p*(1-p)}{n} }$

If n=1139 and p =0.96, the standard deviation is:

$\sigma=\sqrt{\frac{p*(1-p)}{n}}\\\sigma = 0.001836$

The minimum and maximum usual values are:

$\mu-2\sigma = (p-2\sigma)*n\\\mu+2\sigma = (p+2\sigma)*n$

$\mu-2\sigma = (0.96-2*0.001836)*1139\\\mu-2\sigma = 1,089.26\\\mu+2\sigma = (0.96+2*0.001836)*1139\\\mu+2\sigma = 1,097.62$

5 0

3 years ago

You roll 2 number cubes. What is the probability of rolling double twos?<br> EZ points!

Misha Larkins [42]

Answer:

Step-by-step explanation:

There are 6 ways we can roll doubles out of a possible 36 rolls (6 x 6), for a probability of 6/36, or 1/6, on any roll of two fair dice. So you have a 16.7% probability of rolling doubles with 2 fair six-sided dice.

3 0

2 years ago

Read 2 more answers

Which is an asymptote of the graph of the function y = cot ( x - 2pi / 3 )

vesna_86 [32]

$\bf y=cot\left(x-\frac{2\pi }{3} \right)\implies y=\cfrac{cos\left(x-\frac{2\pi }{3} \right)}{sin\left(x-\frac{2\pi }{3} \right)}$

now, if the denominator turns to 0, the fraction becomes undefined, and you get a "vertical asymptote" when that happens, so let's check when is that

$\bf sin\left(x-\frac{2\pi }{3} \right)=0\implies sin^{-1}\left[ sin\left(x-\frac{2\pi }{3} \right) \right]=sin^{-1}(0)
\\\\\\
x-\frac{2\pi }{3}=
\begin{cases}
0\\
\pi 
\end{cases}\implies \measuredangle x=
\begin{cases}
\frac{2\pi }{3}\\
\frac{5\pi }{3}
\end{cases}$

now, at those angles, the function is asymptotic, check the picture below

3 0

3 years ago

Read 2 more answers