Answer:
Step-by-step explanation:
c^2 = a^2 + b^2
4.5^2 + 9^2 = 101.25
c = sqrt 101.25 = 10.06 = 10.1 meters
Answer:
1) The size of the colony after 4 days is 6553 mosquitoes
2) After
Step-by-step explanation:
To answer this question you must use the growth formula

Where
is the initial population of mosquitoes = 1000
t is the time in days
k is the growth rate
N is the population according to the number of days
We know that when t = 1 and
then N = 1600
Then we use these values to find k.

Now that we know k we can find the size of the colony after 4 days.

To know how long it should take for the population to reach 10,000 mosquitoes we must do N = 10000 and solve for t.

Answer:
174.6 ft
Step-by-step explanation:
It can be helpful to draw a diagram of the triangle we're concerned with. (See attached.)
We know the angle at the end of the shadow inside the triangle is 52°-22° = 30°. We assume the tree is growing straight up out of the hillside, so its angle with the hill inside the triangle is 90°+22° = 112°. Then the remaining angle between the shadow and the tree at the top of the tree is ...
180° -30° -112° = 38°
Now, we have the angle opposite the tree, and the angle opposite the known side length of the triangle (215 feet along the hill, AC in the diagram). This is enough information to usefully use the Law of Sines.
c/sin(C) = a/sin(A)
c = a(sin(C)/sin(A)) = (215 ft)(sin(30°)/sin(38°)) ≈ 174.6 ft
The height of the tree is about 174.6 feet.
So, when adding in the 7 and 3 the new equation is:
9{(9x7)+(4x3)+9}
Following pemdas, you have to do parenthesis first. So now the equation is:
9(63+12+9)
Now distribute the 9:
567 + 108 + 81
And finally solve as a normal addition problem:
567 + 108 + 81= 756
So, the answer is 756.
I hope this helps:)
Answer with Step-by-step explanation:
We are given that

We have to explain that why the function is discontinuous at x=2
We know that if function is continuous at x=a then LHL=RHL=f(a).

LHL=Left hand limit when x <2
Substitute x=2-h
where h is small positive value >0


Right hand limit =RHL when x> 2
Substitute
x=2+h


LHL=RHL=
f(2)=1

Hence, function is discontinuous at x=2