What part of the hair extends from the papilla to the body surface

Eukaryotic cells. Classify each statement according to whether it occurs in eukaryotic cells, prokaryotic cells, or both.

frutty [35]

Answer:

Both:

The start codon is often AUG

Eukaryotic cell only:

The larger subunit of the ribosome is 60s.
The ribosomes initially binds the 5' end of mRNA.

Prokaryotic cell only:

The ribosome is 70s
Translation occurs in the cytoplasm
There are multiple ribosome binding site

Explanation:

AUG is the common start codon for both eukaryotic as well prokaryotic cells. In eukaryotic cell, it codes for methionine . While in prokaryotic cell, it codes for formyl methionine.
In prokaryotic cell, ribosomes are found in cytoplasm, hence the translation occurs in cytoplasm.
Eukaryotic ribosome consists of two subunits; 40s and 60s(larger subunit)
Prokaryotic ribosomes have 70s ribososme, which consists of 50s and 20s subuints
in eukaryotic cell, 40s ribosome initially binds to the cap at the 5' end of mRNA.
Bacterial mRNA contain multiple ribosome binding sites.

8 0

3 years ago

What does research say about the relationship between birth order, sibling spacing, and intelligence?

vesna_86 [32]

Answer:

"Birth order and sibling spacing are unrelated to a child's intelligence."

Explanation:

The theory, put forward by Robert Zajonc, a psychologist at the University of Michigan, holds, in brief, that the greater the number of children in a family and the shorter the time between their births, the lower will be the intelligence of the children, particularly those born later. A mother's genetics determines how clever her children are, according to researchers, and the father makes no difference. Women are more likely to transmit intelligence genes to their children because they are carried on the X chromosome and women have two of these, while men only have one.

6 0

3 years ago

1. What is the total magnification of an object if the ocular lens magnification is 20x and the objective lens magnification is

V125BC [204]

1. Answer: 900x

A typical microscope has two lens: ocular lens which located near the eye, and objective lens which located near the object. The image will undergo magnification of both lens. The total magnification of the object would be the product of both lens multiplication, not the sum. The multiplication will be: 20x * 45x= 900x

total mag= ocular * object

total mag= 20x * 45x

total mag= 900x

2. Answer: 100x

The total magnification of the object would be the product of both lens multiplication. If the total magnification 1000x, that mean it was the product of ocular lens and objective lens. If ocular lens magnification is 10x, objective lens magnification would be:

total mag= ocular * object

1000x= 10x*object

object=1000x/ 10x=

object=100x

3. Answer: 0.2 mm

The area of the microscope that can be viewed by the eye should be the same. But since the magnification is different, the actual area that it represent will be different. Microscope with bigger magnification will have smaller diameter of the field of view(DFV). Remember that micrometer(μm) is 1/1000 of millimeter(mm). The DFV would be:500 μm/ ( 1000x/400x)= 200μm= 0.2 mm

4. Answer: 750μm

This question is similar to number 3 question. Remember that 1 millimeter(mm) equal to 1000 micrometer(μm) .

The DFV of a 10x objective lens is 3 mm. Then the DFV of 40x lens would be:

DFV2= DFV1/ (mag1/mag2)

DFV2= 3mm/ ( 40x/10x)= 0.75 mm= 750μm

5. Answer: 125μm x 37.5μm

The lens DFV of microscope from question 4 is 750μm, so the width and length of the area would be 750μm.

If 6 organisms could fit across the DFV if they were laid end-to-end, the length would be: 750μm/ 6 organism= 125μm

If 20 organism could fit is stacked side by-side, then the width would be: 750μm/ 20 organism= 37.5μm

6. Answer: 6mm

This question is similar to number 3 and number 4 question. Remember that 1 millimeter(mm) equal to 1000 micrometer(μm).

The DFV of a 100x objective lens is 1.5 mm. Then the DFV of 25x lens would be:

DFV2= DFV1/ (mag1/mag2)

DFV2= 1.5mm/ (100x/25x)= 6 mm

7.Using the 100x objective lens from question 6, you estimate 12 organisms could fit across the DFV if they were laid end-to-end and 30 could fit is stacked side-by-side. What is the length and width of this organism (in microns)?

Answer: 0.5mm x 0.2mm or 500μm x 200μm

The lens DFV of microscope from question 6 is 6 mm, so the width and length of the area would be 6 mm.

If 12 organisms could fit across the DFV if they were laid end-to-end, the length would be: 6mm/ 12 organism=0.5mm

If 30 organism could fit is stacked side by-side, then the width would be: 6mm/ 30 organism= 0.2mm

6 0

3 years ago

Help i don’t understand this question

Setler79 [48]

Yeah same mansion that

5 0

3 years ago

BRAINLIEST 20 POINTS ANSWER THESE QUESTIONS

yarga [219]

1. An underdeveloped DNA molecule would result in mutations. On the genetic level, this could mean entire traits are deleted or that an early stop occurs in transcription, which could cut off parts of instructions.

2. Genetic code is the nucleotide sequence of a gene while the gene expression is how these sequences are used to make functioning amino acids and proteins to create DNA.

3. In each cell itself there are roughly 42 million proteins.

4 0

3 years ago