1- 8s^300+0.75s^100
2- 27x^2yz+21xz-2yzx-2y^2z+2yz^2
Hope this helps
Answer:
The difference (in km) between what Kayden ran and what Jayden ran is, 7.867 km.
Step-by-step explanation:
The information provided is as follows:
- Kayden ran 8 km.
- Cayden ran half of distance Kayden ran.
- Isaac ran 1/5 of the distance Cayden ran.
- Jayden ran 1/6 of what Isaac ran.
So, using the given information it can be said that Cayden ran 4 km.
Then the distance Isaac ran is, .
Then the distance Jayden ran is,
Compute the difference (in km) between what Kayden ran and what Jayden ran as follows:
Thus, the difference (in km) between what Kayden ran and what Jayden ran is, 7.867 km.
A = P ( 1+r )^ t
A = the future value including interest
P = the principal = $15,000
r = the annual interest rate = 6% = 0.06
t = the number of years = 5 years
So
A = 15,000(1 + 0.06)^5
A = $20,073.38
Answer
She will have paid $20,073.38 at the end of the five year
21.0
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The answer is -36 because
13,6,-1,-8,-15,-22,-29,-36