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suter [353]
3 years ago
11

Sixteen increased by twice a number is 36 find the number

Mathematics
2 answers:
Marina CMI [18]3 years ago
8 0
16 + 2n= 36

hope this helps . give brainliest 
thanks 
Paladinen [302]3 years ago
5 0
So it's 16 plus double the number we need is 36, 36 - 16 = 20 20 / 2 = 10
The number is 10
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Price of Rope
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The answer is 2.25 that makes profit

Step-by-step explanation:

6 0
3 years ago
Learning Task 1. Group the given equations into two based on observed common properties.
AnnZ [28]

Quadratic Equations in Single Variable

n²-3n+10=0

2x²+2x+1=0

25b²-16=0

f²-3f+2=0

1/3m +2m=4

a²=225

Linear Equation in single Variable

8-3k=12

5w+5=0

10u-5=8

Linear Equation in Two  Variable

2y-z=9

3r+2e=6

d=3e-7

<h3>What is an equation?</h3>

It should be noted that an equation simply means the expression that's used to show the relationship between the variables.

In this case, the equation has been grouped.

Learn more about equations on:

brainly.com/question/2972832

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Group the given equations into two based on observed common properties.

Equations

n²-3n+10=0

8-3k=12

2y-z=9

2x²+2x+1=0

25b²-16=0

3r+2e=6

5w+5=0

f²-3f+2=0

d=3e-7

1/3m +2m=4

10u-5=8

a²=225

6 0
1 year ago
Solve:<br>log2 3√(2)/ 16 = s​
jek_recluse [69]

Answer:

log1/8

Step-by-step explanation:

3 0
4 years ago
Nico can do 42 push-ups in 3 minutes.
Alchen [17]

Step-by-step explanation:

Hey there!

It is said we need to find the unit rate.

What we can do is apply Unitary Method.

3 minutes = 42 push ups

1 minute = \sf{\bf{\dfrac{42}{3}}}

<u>So, 12 push ups per minute is the unit rate.</u>

In 5 minutes, he will do 12×5 = <u>60 push ups!</u>

Hope it helps :)

4 0
3 years ago
Given that k is a positive integer. Find, in terms of k, an expression for Sn, which is the sum of the integers from 2k to 4k in
Elden [556K]

Answer:

S_n=3k\cdot (2k+1)=6k^2 +3k

Step-by-step explanation:

k is a positive integer.

Consider an arithmetic sequence:

a_1=2k\\ \\a_n=4k\\ \\d=1

First, find n:

a_n=a_1+(n-1)\cdot d\\ \\4k=2k+(n-1)\cdot 1\\ \\2k=n-1\\ \\n=2k+1

Now, find the sum of these 2k+1 terms:

S_n=\dfrac{a_1+a_n}{2}\cdot n\\ \\S_n=\dfrac{2k+4k}{2}\cdot (2k+1)=\dfrac{6k}{2}\cdot (2k+1)=3k\cdot (2k+1)=6k^2 +3k

7 0
3 years ago
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