Question

This image shows that when a football is kicked, the nearest defensive player is 6 feet from the kicker’s foot. The height of the punted football, f(x), in feet, can be modeled by the equation. Round all answers to 2 decimals. ()=−0.0152 +1.25+2 a. (2 points) What is the maximum height of the punt?

Answer 1

Using the vertex, it is found that the maximum height of the punt is of 27.7 feet.

The height of the punt, after x seconds, is given by:

$f(x) = -0.0152x^2 + 1.25x + 2$

It is a quadratic equation with coefficients $a = -0.0152, b = 1.25, c = 2$.

The maximum value is the value of the function at the vertex, hence:

$f_V = -\frac{\Delta}{4a} = -\frac{b^2 - 4ac}{4a}$

Applying the coefficients:

$f_V = -\frac{b^2 - 4ac}{4a} = -\frac{(1.25)^2 - 4(-0.0152)(2)}{4(-0.0152)} = 27.7$

The maximum height of the punt is of 27.7 feet.

A similar problem is given at brainly.com/question/16858635