Answer:
1100 field-side tickets and 4500 end-zone tickets.
Step-by-step explanation:
Let x represent number of field side tickets and y represent number of end-zone tickets.
We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:
We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.
Cost of x field side tickets would be 
and cost of y end-zone tickets would be 
.
The total amount of money received for the tickets was $134000. We can represent this information in an equation as:
Upon substituting equation (1) in equation (2), we will get:
Therefore, 1100 field side tickets were sold.
Upon substituting in equation (1), we will get:
Therefore, 4500 end-zone tickets were sold.
Answer:
Step-by-step explanation:
I guess they never miss huh
Answer:
Step-by-step explanation:
<h3>Hope it is helpful...</h3>
Answer:
z= 2.38
P = 0.008656
Step-by-step explanation:
Here n= 500 and p~= 464/500= 0.928 and q`= 1- 0.928 = 0.072
We formulate our null and alternate hypothesis as
H0 = 0.9 ; H0 > 0.9
The degree of confidence = 90%
z₀.₀₅ = 1.645 for α= 0.05
We use the test statistic
z= x- np/√npq
z= 466-500 *0.9/ √500 * 0.9(1-0.9)
z= 466- 450/ √45
z= 16/6.7082
z= 2.38
As the calculated value of z= 2.38 is greater than α =1.645 so we reject H0.
If H0 is true the P value is calculated as
P = 1- Ф( 2.38)
P = 1-0.991344=0.008656
4 pieces of pipe,
4/3 yd long
25/6 yd long
5 pieces same length.
(25/6)/5 = 5/6 yd is the length of each piece of woods.
