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Lilit [14]
3 years ago
13

Which quadratic equation has no real roots?

Mathematics
2 answers:
Stella [2.4K]3 years ago
6 0

Answer:

The first choice and the last have no real roots.

Step-by-step explanation:

For an equation to have no real roots the value of the discriminant ( b^2 - 4ac) will be negative.

Working out the values:

1.  D = (-2)^2 - 4* -1*-6 = -20 so it has no real roots.

2. D = (3)^2 - 4*  -2* 4 =  41 so it does have real roots.

3. D = (1)^2 - 4* 2*-6 = 49 so real roots.

4. D =   (-1)^2 - 4* 2*3 = -23 so  no real roots

n200080 [17]3 years ago
3 0

Answer:

A and D

Step-by-step explanation:

By finding the roots of all the equations, we see that options A and D are the only ones that require an imaginary number in order to solve

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Reil [10]

Answer:

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Step-by-step explanation:

Those are the answers on edginuity.

6 0
3 years ago
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Ber [7]

Answer:

b = 29

Step-by-step explanation:

C x D = A x B

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3 years ago
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Answer:

2x(x-7)+3(x-7)

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6 0
3 years ago
2(m + 1) = 16 <br> full answer
Serhud [2]

Answer:

2m+2=16, then do the isolate m but doing the inverse operation of 2 which is now -2 and add that to 16 would be left with 2m=14 and 14/2 is 7 so m=7

Step-by-step explanation:

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