Which quadratic equation has no real roots?
2 answers:
Answer:
The first choice and the last have no real roots.
Step-by-step explanation:
For an equation to have no real roots the value of the discriminant ( b^2 - 4ac) will be negative.
Working out the values:
1. D = (-2)^2 - 4* -1*-6 = -20 so it has no real roots.
2. D = (3)^2 - 4* -2* 4 = 41 so it does have real roots.
3. D = (1)^2 - 4* 2*-6 = 49 so real roots.
4. D = (-1)^2 - 4* 2*3 = -23 so no real roots
Answer:
A and D
Step-by-step explanation:
By finding the roots of all the equations, we see that options A and D are the only ones that require an imaginary number in order to solve
You might be interested in
Answer:
x=2
Step-by-step explanation:
5(x-5)=3(x-7)
Distribute
5x-25 = 3x-21
subtract 3x from each side
5x-25-3x = 3x-21-3x
2x-25 = -21
Add 25 to each side
2x-25+25 = -21 +25
2x=4
Divide by 2
2x/2 =4/2
x=2
Answer:
1/135
Step-by-step explanation:
subtract the 1 from 17/15
you get 2/15 and then you multiply that by 1/18
Hello,
It is the Fibonacci 's suit.
Step-by-step explanation:
Substitute r = 3 and h = 5 into the formula. Volume V=13⋅π⋅9⋅5=15πcm3=47.1cm3.
Answer:
40m^2
Step-by-step explanation:
Hope it helps!!:)
