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4 years ago

14

A flowerpot falls off a windowsill and passes the win- dow of the story below. Ignore air resistance. It takes the pot 0.380 s t

o pass from the top to the bottom of this window, which is 1.90 m high. How far is the top of the window below the window- sill from which the flowerpot fell?

1 answer:

stich3 [128]4 years ago

4 0

Answer:

d = 0.50 m

Explanation:

Let say the speed at the top and bottom of the window is

$v_1 \: and \: v_2$ respectively

now we have

$d = \frac{v_1 + v_2}{2}t$

$1.90 = \frac{v_1 + v_2}{2} (0.380)$

$v_1 + v_2 = 10$

also we know that

$v_2 - v_1 = 9.8(0.380)$

$v_2 - v_1 = 3.72$

now we have from above equations

$v_2 = 6.86 m/s$

$v_1 = 3.14 m/s$

now the distance from which it fall down is given as

$v_f^2 - v_i^2 = 2ad$

$3.14^2 - 0^2 = 2(9.8)d$

$d = 0.50 m$

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A square is 1.0 m on a side. Point charges of +4.0 μC are placed in two diagonally opposite corners. In the other two corners ar

finlep [7]

Answer:

<em>B) 1.0 × 10^5 V</em>

Explanation:

<u>Electric Potential Due To Point Charges </u>

The electric potential produced from a point charge Q at a distance r from the charge is

$\displaystyle V=k\frac{Q}{r}$

The total electric potential for a system of point charges is equal to the sum of their individual potentials. This is a scalar sum, so direction is not relevant.

We must compute the total electric potential in the center of the square. We need to know the distance from all the corners to the center. The diagonal of the square is

$d=\sqrt2 a$

where a is the length of the side.

The distance from any corner to the center is half the diagonal, thus

$\displaystyle r=\frac{d}{2}=\frac{a}{\sqrt{2}}$

$\displaystyle r=\frac{1}{\sqrt{2}}=0.707\ m$

The total potential is

$V_t=V_1+V_2+V_3+V_4$

Where V1 and V2 are produced by the +4\mu C charges and V3 and V4 are produced by the two opposite charges of $\pm 3\mu\ C$ . Since all the distances are equal, and the charges producing V3 and V4 are opposite, V3 and V4 cancel each other. We only need to compute V1 or V2, since they are equal, but they won't cancel.

$\displaystyle V_1=V_2=k\frac{Q}{r}=9\times 10^9 \frac{4\times 10^{-6}}{0.707}$

$V_1=V_2=50912\ V$

The total potential is

$V_t=50912\ V+50912\ V=1\times 10^5\ V$

$\boxed{V_t=1\times 10^5\ V}$

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3 years ago

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meriva

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Explanation:

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3 years ago

Read 2 more answers

A skateboarder travels on a horizontal surface with an initial velocity of 4.0 m/s toward the south and a constant acceleration

Alenkinab [10]

Answer:

a) 0.32 m b) -2.4 m c) 1.08 m/s d) -4 m/s

Explanation:

a)

As the x and y axes (as chosen) are perpendicular each other, the movements along these axes are independent each other.
This means that we can use the kinematic equations for displacements along both axes.
In the x direction, as the only initial velocity is in the south direction (-y axis), the skateboarder is at rest, so we can write:

$x =\frac{1}{2}*a*t^{2} (1)$

In the y-direction, as no acceleration is acting on the skateboarder, we can write the following displacement equation:

$y = v_{0y} * t (2)$

For t = 0.6s, replacing by the givens, we get the position (displacement from the origin) on the x-axis, as follows:

$x =\frac{1}{2}*a*t^{2} =\frac{1}{2} * 1.8 m/s2*(0.6s)^{2}\\ x = 0.32 m$

b)

From (2) we can get the position on the y-axis (displacement from the origin) as follows:

$y = v_{0y} * t = -4 m/s * 0.6 s = -2.4 m$

c)

In the x- direction, we can find the component of the velocity along this direction, as follows:

$v_{fx} = a*t$

Replacing by the values, we have:

$v_{fx} = a*t = 1.8 m/s2 * 0.6 s = 1.08 m/s$

d)

As the skateboarder moves along the y-axis at a constant speed equal to her initial velocity, we have:

vfy = voy = -4 m/s

8 0

4 years ago

Sam drives her scooter 7 kilometres north. She stops for lunch and then drives

Talja [164]

Answer:

1. Distance travelled = 12 km.

2. Displacement = 8.6 km

Explanation:

From the question given above, the following data were obtained:

Distance 1 (d₁) = 7 km

Distance 2 (d₂) = 5 km

Total distance =?

Displacement =?

1. Determination of the distance travelled.

Distance 1 (d₁) = 7 km

Distance 2 (d₂) = 5 km

Total distance (dₜ) =?

dₜ = d₁ + d₂

dₜ = 7 + 5

dₜ = 12 km

2. Determination of the displacement.

In the attached photo, R is the displacement.

We can obtain the value of R by using the pythagoras theory as illustrated below:

R² = 7² + 5²

R² = 49 + 25

R² = 74

Take the square root of both side

R = √74

R = 8.6 km

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3 years ago

5. From the definition of work, explain why only the vertical height of the stairs is measured. Hint: Think of the data table co

natulia [17]

The motivation behind why the vertical stature of the stairs is the main thing measured is that it uncovers to us how much gravity is up against the individual and their weight, so we require this data to decide how much vitality and power we have to get up the stairs.

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4 years ago