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Delicious77 [7]
3 years ago
6

Number of conducting plates of a multiplate capacitor is 5. The no. Of capacitors is

Physics
1 answer:
Ivahew [28]3 years ago
8 0

Answer:

4 capacitors

Explanation:

Given

n = 5 --- conducting plates

Required

The number of capacitor (c)

This is calculated as:

c = n - 1

So, we have:

c = 5 - 1

c = 4

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mgsinФ - f_{r} = ma

3 * 9.8 * sin 37 - f_{r} = 3* 0.4

17.9633 - f_{r} =  1.2

f_{r} = 17.9633 - 1.2

f_{r} = 16.49N

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