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Darya [45]
3 years ago
13

The general equation for depreciation is given by y = A(1 – r)t, where y = current value, A = original cost, r = rate of depreci

ation, and t = time, in years. A car was purchased 6 years ago for $25,000. If the annual depreciation rate is 11%, which equation can be used to determine the approximate current value of the car?
A. y=25,000(.89)^6
B. y=(25,000 x .11)^6
C. y=(25,000 x .89)^6
D.y=25,000(.11)^6

note: the 'x' is a multiplication symbol
Mathematics
2 answers:
sergij07 [2.7K]3 years ago
5 0

Answer:

A. y=25,000(.89)^6

Step-by-step explanation:

answer on edge 2020

i just took the quiz and got it right

hope this helps!!!

irina1246 [14]3 years ago
3 0
Analyzing the given values and the given equation, we have the following:
A = $25,000
r = 0.11
t = 6

The equation has the form:
y = A (1-r)^t
Plugging in the given values into the equation,
y = $25,000 (1 - 0.11)^6
y = $25,000 (0.89)^6

Therefore, the answer is
A. y=25,000(.89)^6
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\dfrac{\cos^3A-\cos A}{\sin^3A-\sin A}+\dfrac{\cos^2A-\cos^4A}{\sin^4A-\sin^2A}=\dfrac{\sin A}{\cos^2A\cos^3A}\\\\L_s=\dfrac{\cos A(\cos^2A-1)}{\sin A(\sin^2A-1)}+\dfrac{\cos^2A(1-\cos^2A)}{\sin^2A(\sin^2A-1)}\\\\=\dfrac{\cos A(-\sin^2A)}{\sin A(-\cos^2A)}+\dfrac{\cos^2A\sin^2A}{\sin^2A(-\cos^2A)}\\\\=\dfrac{\sin A}{\cos A}-1=\tan A-1

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