Given :
As a plane takes off it ascends at a 20 degree angle of elevation.
If the plane has been travelling at an average rate of 290 ft/s and continues to ascend at the same angle.
To Find :
How high is the plane after 10 seconds.
Solution :
Distance travelled by plane, D = 2900 ft.
Angle of elevation, Ф = 20°.
Height gained is given by :
H = 2900 × sin 20°
H = 991.86 ft.
Therefore, height of plane after 10 seconds is 991.86 ft.
Hence, this is the required solution.
Answer:
Step-by-step explanation:
r = 8.35 ft
area of circle = πr² = 69.7225π ft²
θ = 5π/9 radians
area of unshaded segment = r²(θ-sinθ)/2 ≅ 26.51 ft²
shaded region = 69.7225π - 26.51 ≅ 192.53 ft²
Answer:
I'm pretty sure it's +(-6).
Step-by-step explanation:
Basically for these, you find the slope. The slope equation is y1-y2/x1-x2.
Pick two points.
I'll just do (1,15) and (2,9).
15-9/1-2 = 6/-1 = -6.
I don't know if you were taught it this way, but my math teacher always told us that the rate of change had to be positive.
So you'd say the rate of change is +(-6), not -6.
Hope that sorta helped lol
167+57 written in base ten method
Answer:
1.69 kg
Step-by-step explanation:
add than subtract
yep thats it
