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Alexxx [7]
3 years ago
14

Wapi simplified an expression. His work is shown below.

Mathematics
2 answers:
posledela3 years ago
8 0

Answer:i did it on edg and i got 100 on test its step 3

Step-by-step explanation:

I got 100 :D

-BARSIC- [3]3 years ago
5 0

Answer:

Step 3

Step-by-step explanation:

7( 8.5-1.5) +8 ÷2

PEMDAS

Parentheses

7*7 +8 ÷2

Then multiplication and division from left to right

49 +8 ÷2

We are still on multiplication and division

49+4

So step 3 is the first mistake

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4+p over 14 = 1 need help
lukranit [14]

Answer:

p = 10

Step-by-step explanation:

In order to solve an equation we must isolate the variable we're solving for, p.

We can do this by undoing operations in the equation.

First, multiply both sides of the equation by 14.

\frac{4+p}{14} * 14 = 1 *14

This gives you 4 + p = 14

Then, you can subtract 4 from both sides:

4 - 4 + p = 14 - 4

p = 10

6 0
3 years ago
The number of bagels sold daily for two bakeries is shown in the table. Bakery A Bakery 45, 52, 51, 48, 57, 30, 55, 46 Bakery B
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D-median, because the presence of an outlier affect the data

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3 years ago
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Through:(-1,-5), slope=5
Travka [436]
What exactly are you looking for?

7 0
3 years ago
The lifetime of LCD TV sets follows an exponential distribution with a mean of 100,000 hours. Compute the probability a televisi
kondaur [170]

Answer:

0.9

0.3012

0.1809

230258.5

Step-by-step explanation:

Given that:

μ = 100,000

λ = 1/μ = 1 / 100000 = 0.00001

a. Fails in less than 10,000 hours.

P(X < 10,000) = 1 - e^-λx

x = 10,000

P(X < 10,000) = 1 - e^-(0.00001 * 10000)

= 1 - e^-0.1

= 1 - 0.1

= 0.9

b. Lasts more than 120,000 hours.

X more than 120000

P(X > 120,000) = e^-λx

P(X > 120,000) = e^-(0.00001 * 120000)

P(X > 120,000) = e^-1.2

= 0.3011942 = 0.3012

c. Fails between 60,000 and 100,000 hours of use.

P(X < 60000) = 1 - e^-λx

x = 60000

P(X < 60,000) = 1 - e^-(0.00001 * 60000)

= 1 - e-^-0.6

= 1 - 0.5488116

= 0.4511883

P(X < 100000) = 1 - e^-λx

x = 100000

P(X < 60,000) = 1 - e^-(0.00001 * 100000)

= 1 - e^-1

= 1 - 0.3678794

= 0.6321205

Hence,

0.6321205 - 0.4511883 = 0.1809322

d. Find the 90th percentile. So 10 percent of the TV sets last more than what length of time?

P(x > x) = 10% = 0.1

P(x > x) = e^-λx

0.1 = e^-0.00001 * x

Take the In

−2.302585 = - 0.00001x

2.302585 / 0.00001

= 230258.5

3 0
3 years ago
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The statement on the bottom left is correct. (6 students studied for 20 to 24 hours)

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