3 years ago

What x something negative = +8?

Mathematics

1 answer:

devlian [24]3 years ago

8 0

it dependss on the value of the x

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Find a counterexample to show that the conjecture is false. The product of two positive numbers is always greater than either nu

jekas [21]

Answer:

$\frac{1}{2}$ × $\frac{1}{4}$ = $\frac{1}{8}$

Step-by-step explanation:

This sentence isn't always true.

here is a counter example :

The trick is to use fractional numbers .

$\frac{1}{2}$ × $\frac{1}{4}$ = $\frac{1}{8}$

let's analyse this example :

$\frac{1}{2}$ $\geq$ $\frac{1}{8}$ and $\frac{1}{4}$ $\geq$ $\frac{1}{8}$

1/2=0.5 and 1/4=0.25 but 1/8=0.125

0.125<0.25<0.5

here is another example : (1/2)*(1/3)=1/6
the same thing : 1/6<1/3<1/2

4 0

3 years ago

Help me out I can’t figure out how to do this

serious [3.7K]

Check the picture below.

$\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=\frac{1}{4} \end{cases}\implies V=\cfrac{4\pi \left( \frac{1}{4} \right)^3}{3}\implies V=\cfrac{4\pi\frac{1}{64}}{3} \\\\\\ V=\cfrac{\frac{4\pi}{64}}{3}\implies V=\cfrac{\frac{\pi}{16}}{\frac{3}{1}}\implies V=\cfrac{\pi }{16}\cdot \cfrac{1}{3}\implies V=\cfrac{\pi }{48}\implies \stackrel{\textit{rounded up}}{V=0.07}$