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Andrews [41]
3 years ago
14

3-5x in verbal expression

Mathematics
1 answer:
Wittaler [7]3 years ago
6 0
5 times a number subtracted from 3.

Hope this helps!
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PLZ HELP! Use technology or a z-score table to answer the question.
Rashid [163]

Answer:

the answer would be A, or 5.3%

Step-by-step explanation:

you start by finding the z-score of 200, so 200-144.05 = 55.95/34.52 = 1.62 (rounded to the nearest ) Then you use a z-score table to find the probability that a customer will spend less than 200 dollars and subtract the decimal probability from one. then you convert the decimal probability to a percent and get 5.3%.

7 0
3 years ago
Parker bought a 15-year treasury bond for a face amount of $400. The 3.5% interest will be compounded quarterly. What will the f
MArishka [77]
If you're behind like I am and are just now doing these assignments then good luck on catching up.

If it's AQRB Unit 2 Lesson 3 then the answers to the multiple choice are below, you'll need to do the essay and calculation on your own.

1: $674.64
2: $26, 255.38
3: $191, 398.49
4: $23, 884.84
6 0
4 years ago
The random variable X~(30,2^2) <br> Find p(X&lt;33) <br> Find p(X&gt;26)
Ostrovityanka [42]

Answer:

i) P(X<33)  = 0.9232

ii) P(X>26) = 0.001

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the mean of the Population = 30

Given that the standard deviation of the Population = 4

Let 'X' be the Normal distribution

<u>Step(ii):-</u>

i)

Given that the random variable  X = 33

               Z = \frac{x-mean}{S.D}

               Z = \frac{33-30}{2} = 1.5 >0

P(X<33) = P( Z<1.5)

              = 1- P(Z>1.5)

             = 1 - ( 0.5 - A(1.5))

             = 0.5 + 0.4232

  P(X<33)  = 0.9232

<u>Step(iii) :-</u>

Given that the random variable  X = 26

               Z = \frac{x-mean}{S.D}

               Z = \frac{33-26}{2} = 3.5 >0

P(X>26)  = P( Z>3.5)

              = 0.5 - A(3.5)

              = 0.5 - 0.4990

             = 0.001

P(X>26) = 0.001

5 0
3 years ago
Equal set is equivalent set but equivalent set not need equal set? why​
nasty-shy [4]
Equal sets have the exact same elements, so they must have the same number of elements. Therefore, equal sets must also be equivalent. No, not all equivalent sets are also equal sets
6 0
3 years ago
Which functions are symmetric with respect to the y axis<br>​
Inessa05 [86]

Answer:

A, B, and D

Step-by-step explanation:

Only the functions that have x by itself between the absolute value signs (A, B, and D) are symmetric with respect to the y-axis .

Placing a constant outside the absolute value signs moves the function up or down the y-axis but retains the symmetry.

Adding a constant inside the absolute value signs (as in C and E) moves the axis of symmetry to the left or right of the y-axis.

In the diagram, both A and B are symmetric with respect to the y-axis, but C has been shifted three units to the left.

4 0
3 years ago
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