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3 years ago

9

Equal set is equivalent set but equivalent set not need equal set? why

1 answer:

nasty-shy [4]3 years ago

6 0

Equal sets have the exact same elements, so they must have the same number of elements. Therefore, equal sets must also be equivalent. No, not all equivalent sets are also equal sets

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How to solve -4{1-2x}-1=7x

mina [271]

Answer:

<h2>x = 5</h2>

Step-by-step explanation:

$-4(1-2x)-1=7x\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\(-4)(1)+(-4)(-2x)-1=7x\\\\-4+8x-1=7x\qquad\text{combine like terms}\\\\8x+(-4-1)=7x\\\\8x-5=7x\qquad\text{add 5 to both sides}\\\\8x-5+5=7x+5\\\\8x=7x+5\qquad\text{subtract}\ 7x\ \text{from both sides}\\\\8x-7x=7x-7x+5\\\\x=5$

7 0

3 years ago

Read 2 more answers

Is there any option to to 1 not be equal to 1?

r-ruslan [8.4K]

No. 1 is is always equal to to 1 .

4 0

3 years ago

Not sure about this please help!!!

harina [27]

Answer:

i think its the last one

Step-by-step explanation:

as 15 - 3 is 12 and then the 7

hope this helps

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8 0

3 years ago

What is the area of a triangle with vertices (3,0) (9,0) (7,6)

Nezavi [6.7K]

Answer:

The area of the triangle is of 21 units of area.

Step-by-step explanation:

The area of a triangle with three vertices $(x_1,y_1),(x_2,y_2),(x_3,y_3)$ is given by the determinant of the following matrix:

$A = \pm 0.5 \left|\begin{array}{ccc}x_1&y_1&1\\x_2&y_2&1\\1_3&y_3&1\end{array}\right|$

In this question:

Vertices (3,0) (9,0) (7,6). So

$A = \pm 0.5 \left|\begin{array}{ccc}3&0&1\\9&0&1\\7&7&1\end{array}\right|$

$A = \pm 0.5(3*0*1+0*1*7+1*9*7-0*7*1-0*9*1-3*1*7)$

$A = \pm 0.5*(63-21)$

$A = \pm 0.5*42 = 21$

The area of the triangle is of 21 units of area.

5 0

3 years ago

How many terms are in the expression 4x -4 +3y?

horrorfan [7]

Answer:

three (3)

Step-by-step explanation:

4x is the first term

-4 is the second term

3y is the third term

7 0

3 years ago