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Svet_ta [14]
3 years ago
13

Find the equation of the line containing the points (-3, -10) and (12, 0)

Mathematics
1 answer:
Gre4nikov [31]3 years ago
6 0
The equation is y= (2/3)x - 8. Hope this helps

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Find the diffrence between temperature -30 degrees c and 70 degrees c?
andreyandreev [35.5K]
One is colder than the other. 
     Hope this helps :)
4 0
3 years ago
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If f(x) = x2 -1, what is the equation for f–1(x)?
professor190 [17]
Evaluate the function would be= x^2-f-x
3 0
3 years ago
What is the sum of the roots of the quadratic equation x²+6x-14=0?​
aivan3 [116]

Answer:

<h3>Sum of Roots =<u> (-8)</u><u> </u><u> </u></h3><h3>Product of Roots = <u> </u><u> </u><u>(-84)</u><u> </u><u> </u></h3>

Step-by-step explanation:

{x}^{2}  + 6x - 14 = 0

Roots :- 6 and -14

Sum of the roots :

[6 + (-14)]

= (-8)//

Product of the roots :

[(6)(-14)]

= (-84)//

8 0
2 years ago
Is 4/7 greater or less than 3/5
baherus [9]
No, it is not.

4/7 ≈ 0.5714

3/5 = 0.6

Actually, 3/5 is greater than 4/7.

Another way you could do this is by multiplying 4/7 with 5/5 and by multiplying 3/5 with 7/7.

4/7 * 5/5 = 20/35

3/5 * 7/7 = 21/35

Have an awesome day! :)
6 0
3 years ago
A rectangular gasoline tank can hold 45.0 kg of gasoline when full. what is the depth of the tank if it is 0.450 m wide by 0.900
garri49 [273]
The answer is 0.154 m

Step 1. Calculate the volume of gasoline tank (V) using the known mass (m) and density of gasoline (D).
D = m/V
⇒   V = m/D
D = 719.7 kg/m³
m = 45.0 kg
V = 45.0 kg/719.7 kg/m³ = 0.0625 m³

Step 2. Calculate the depth of the tank (d) using the known volume (V) of gasoline and width (w) and length (l) of the tank:
V = d * w * l
0.0625 = d * 0.900 * 0.450
0.0625 = d * 0.405
d = 0.0625  / 0.405
d = 0.154 m
7 0
3 years ago
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