Two hot-air balloons, one red and one blue, took off at the same time from different platforms. Each began ascending at a consta
nt rate. The following equation gives the height (in meters) of the red hot-air balloon as a function of time (in seconds). h=1/2t+4 The height (in meters) of the blue hot-air balloon as a function of time (in seconds) is given by the following table of values: (Table is attached) Which balloon started at a greater height? A. The red balloon B. The blue balloon C. They are both the same height
1 answer:
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Answer: The ball hits the ground at 5 s
Step-by-step explanation:
The question seems incomplete and there is not enough data. However, we can work with the following function to understand this problem:
(1)
Where models the height of the ball in meters and
the time.
Now, let's find the time when the ball Sara kicked hits the ground (this is when
):
(2)
Rearranging the equation:
(3)
Dividing both sides of the equation by :
(4)
This quadratic equation can be written in the form , and can be solved with the following formula:
(5)
Where:
Substituting the known values:
(6)
Solving we have the following result:
This means the ball hit the ground 5 seconds after it was kicked by Sara.