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mixer [17]
4 years ago
6

The weight of an object on a particular scale is 145,2 lbs. The measured

Mathematics
1 answer:
Harrizon [31]4 years ago
6 0

Answer:

145.2 + .3 = 145.5

145.2 - .3 = 144.9

C. 144.9 <= x <= 145.5

Step-by-step explanation:

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7. If F(x) = f(g(x)), where f(-2) = 8, f'(-2) = 4, f'(5) = 3, g(5)=-2, gʻ(5) = 6.. Find F'(5) <br>​
serious [3.7K]

Answer:

I'm going to lay this out in a chart so it's a little easier to see:

F(x) = f(g(x))

x | f (x) | f ' (x) | g (x) | g ' (x)

--------------------------------------

-2 | 8 | 4 |

5 | | 3 | -2 | 6

Remember the chain rule, which says

(f (g (x))) ' = g ' (x) f ' (g (x))

When they ask for F ' (5), they are asking for (f (g (x))) ' when x = 5.

Using the chain rule, that's

F ' (5) = g ' (5) f ' (g (5))

We can simplify using the numbers provided.

F ' (5) = (6) f ' (-2)

F ' (5) = (6) (4)

F ' (5) = 24

I hope that helps!

by jannat <33

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Answer:

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Step-by-step explanation:

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A right cylinder has a radius of 6 m and a surface area of 84 m². Find the surface area of a similar cylinder with a radius of 2
dlinn [17]

Answer:

The surface area of the second cylinder is equal to 9.33\ m^{2}

Step-by-step explanation:

we know that

If two figures are similar then

the ratio of their surfaces areas is equal to the scale factor squared

Let

z-------> the scale factor

x------> the surface area of the smaller cylinder (second cylinder)

y-------> the surface area of the original cylinder (first cylinder)

so

z^{2}=\frac{x}{y}

Step 1

Find the scale factor

z=\frac{2}{6}=\frac{1}{3}

Step 2

Find the surface area of the second cylinder

we have

z=\frac{1}{3}

y=84\ m^{2}

substitute and solve for x

(\frac{1}{3})^{2}=\frac{x}{84}

x=\frac{1}{9}*84=9.33\ m^{2}


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What must people taking out a mortgage agree to?
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