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Goshia [24]
3 years ago
13

A right cylinder has a radius of 6 m and a surface area of 84 m². Find the surface area of a similar cylinder with a radius of 2

m.
Mathematics
1 answer:
dlinn [17]3 years ago
5 0

Answer:

The surface area of the second cylinder is equal to 9.33\ m^{2}

Step-by-step explanation:

we know that

If two figures are similar then

the ratio of their surfaces areas is equal to the scale factor squared

Let

z-------> the scale factor

x------> the surface area of the smaller cylinder (second cylinder)

y-------> the surface area of the original cylinder (first cylinder)

so

z^{2}=\frac{x}{y}

Step 1

Find the scale factor

z=\frac{2}{6}=\frac{1}{3}

Step 2

Find the surface area of the second cylinder

we have

z=\frac{1}{3}

y=84\ m^{2}

substitute and solve for x

(\frac{1}{3})^{2}=\frac{x}{84}

x=\frac{1}{9}*84=9.33\ m^{2}


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What is 999 times 100.0​
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Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X &gt; 10) b. P(X &gt; 20) c
GrogVix [38]

Answer:

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(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

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The value of E (X) is 10.

The parameter λ is:

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(a)

Compute the value of P (X > 10) as follows:

P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

P(X

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

P(X

Take natural log on both sides.

ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30

Thus, the value of x is 30.

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