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Alik [6]
3 years ago
10

PLEASE HELP EXTRA POINTS 100 Cingular's plan charged $39.99 per month with $0.45 for each additional minute. Verizon's plan cost

$44.99 with $0.40 for each additional minute. How many additional minutes, A, would it take for the two plans to cost the same?
Mathematics
1 answer:
Anit [1.1K]3 years ago
5 0

44.99-39.99=5.00

5.00÷.45=11.11 additional minutes i would round to 11 because you can't have a fraction of an additional minute.

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We need the diagram pic, otherwise we cant solve your problem.
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2 years ago
ASAP someone please use the Pythagorean Theorem to solve for the missing side of these two right triangles.
solong [7]

Answer:

9) x = 5

10) x = 4

Step-by-step explanation:

a^2 + b^2 = c^2

9) 6^2 + x^2 = 8^2

  - 36 + x^2 = 64

  -  36            - 36

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           x^2 = 28

Square root them

Squareroot x^2 is x

Square root 28 is 5.29 round is 5

so x = 5

*Correct me if im wrong*

10) 3^2 + x^2 = 5^2

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  -  9              - 9

____________________

             x^2= 16

Square root them

square root of x ^2 is x and square root of 16 is 4

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6 0
3 years ago
A runner finished a total of 1500 kilometers in races before retiring she finished thirty-two 15 kilometer races. The rest of he
Triss [41]

Answer:

102 of runner's races were 10-kilometer races.

8 0
2 years ago
Read 2 more answers
Find the geometric mean between each pair of numbers.40 and 15
kirill [66]

Given a N quantity of numbers, the Geometric Mean is equal to the N-th root of product of the N numbers

In this case, we have two numbers, then we need to multiply them and take square root:

\sqrt{40\cdot15}=\sqrt[]{600}=\sqrt[]{100\cdot6}=\sqrt[]{100}\cdot\sqrt[]{6}=10\sqrt[]{6}

The answer is:

10√6

Rounded is Approximately 24.5

8 0
1 year ago
A man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream. Fin
pochemuha

The speed of the current is 40.34 mph approximately.

<u>SOLUTION: </u>

Given, a man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream.  

We have to find the speed of the current if the speed of the boat is 11 mph in still water. Now, let the speed of river be a mph.  Then, speed of boat in upstream will be a-11 mph and speed in downstream will be a+11 mph.

And, we know that, \text{ distance } =\text{ speed }\times \text{ time }

\begin{array}{l}{\text { So, for upstream } \rightarrow 40=(a-11) \times \text { time taken } \rightarrow \text { time taken }=\frac{40}{a-11}} \\\\ {\text { And for downstream } \rightarrow 70=(a+11) \times \text { time taken } \rightarrow \text { time taken }=\frac{70}{a+11}}\end{array}

We are given that, time taken for both are same. So \frac{40}{a-11}=\frac{70}{a+11}

\begin{array}{l}{\rightarrow 40(a+11)=70(a-11)} \\\\ {\rightarrow 40 a+440=70 a-770} \\\\ {\rightarrow 70 a-40 a=770+440} \\\\ {\rightarrow 30 a=1210} \\\\ {\rightarrow a=40.33}\end{array}

8 0
3 years ago
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