3 years ago

Which of the following is the correct expansion of (3x-y)2

Mathematics

1 answer:

GREYUIT [131]3 years ago

4 0

6x-2y (I believe so)

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2 years ago

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Answer:

$(x^\frac{3}{8})^\frac{3}{4} = \sqrt[32]{x^9}$

Step-by-step explanation:

Given

$(x^\frac{3}{8})^\frac{3}{4}$

Required

Convert to radical form

$(x^\frac{3}{8})^\frac{3}{4}$

Evaluate the exponents

$(x^\frac{3}{8})^\frac{3}{4} = x^\frac{3*3}{8*4}$

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Split the exponent

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Apply the following law of indices

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So, we have:

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