You can because it has more then one equal sign
Answer:
Step-by-step explanation:
A tree diagram? I don't think so. Probably it would take a year's supply of paper to record all the possibilities. The question really is do you allow duplications and is 0 allowed to be the first digit.
I would think that both are fine.
So the total number for this number would be 10^9. There probably some sort of algorithm to reduce the number and to check if it is a legitimate choice for this number.
Answer:
Below in BOLD.
Step-by-step explanation:
5x^2 - 6x - 2 = 0
Quadratic formula for ax^2 + bx + c = 0 is
x = [-b ± √(b^2 - 4ac)]/ 2a
Here we have a = 5, b = -6 and c = -2
so x = [-(-6) ± √((-6)^2 - 4*5*-2)]/ 2*5
= [ 6 ± √(36 + 40)] / 10
= 0.6 ± √76 / 10
= 0.6 ± 0.8718
= 1.4718, -0.2718
= 1.5, -0.3 to one decimal place.
x^2 + 3x = 40
x^2 + 3x - 40 = 0
We can factor this one:
(x - 5)(x + 8) = 0
x - 5 = 0 giving x = 5 and
x + 8 = 0 giving x = -8.
Answer x = -8, 5.
Answer:
<u><em>5/8</em></u>
Step-by-step explanation:
first plug in for x & y, then solve. you should get 5/8
2 -2 +5 +0 / 2 +3 +5 -2
<u><em>5/8</em></u>
Answer:
It's is A and D.
Step-by-step explanation:
Tan^2 theta cos 2theta
= (sin^2 theta / cos^2 theta )( 2 cos^2 theta - 1)
= 2 sin^2 theta - sin^2 theta / cos^2 theta
= 2 sin^2 theta - tan^2 theta.
Tan^2 theta cos 2theta
= ( 1 / cot^2 theta) * cos 2theta
= cos 2theta / cot^2 theta.
