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Leto [7]
3 years ago
13

What’s the solution to 8+1/3x=-1

Mathematics
1 answer:
Vlada [557]3 years ago
3 0

8+1/3x=-1

Subtract 8 from both sides

1/3x= -9

Divide 1/3 on both sides

x= -9/1 / 1/3

Flip the second fraction (1/3) while transforming the division sign to multiplication

x= -9/1 * 3/1

Multiply

Final Answer: x= -27

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<ABC would equal 106

seeing in triangle ABD angle A equals 67 you would multiply that by 2 and then subtract it from 180 to get 46, and then triangle DBC all the angles would equal 60. so then add 46 to 60 to get 106 the measure of <ABC

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Answer:

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Step-by-step explanation:

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How do I find a2 and a3 for the following geometric sequence? 54, a2, a3, 128
vlada-n [284]
The formula for the nth term of a geometric sequence:
a_n=a_1 \times r^{n-1}
a₁ - the first term, r - the common ratio

54, a_2, a_3, 128 \\ \\&#10;a_1=54 \\&#10;a_4=128 \\ \\&#10;a_n=a_1 \times r^{n-1} \\&#10;a_4=a_1 \times r^3 \\&#10;128=54 \times r^3 \\&#10;\frac{128}{54}=r^3 \\ \frac{128 \div 2}{54 \div 2}=r^3 \\&#10;\frac{64}{27}=r^3 \\&#10;\sqrt[3]{\frac{64}{27}}=\sqrt[3]{r^3} \\&#10;\frac{\sqrt[3]{64}}{\sqrt[3]{27}}=r \\&#10;r=\frac{4}{3}

a_2=a_1 \times r= 54 \times \frac{4}{3}=18 \times 4=72 \\&#10;a_3=a_2 \times r=72 \times \frac{4}{3}=24 \times 4=96 \\ \\&#10;\boxed{a_2=72, a_3=96}
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