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aleksley [76]
3 years ago
14

If f(x)=x^2-5x+2a. Find 4f(x)b. Find -2f (x)+6​

Mathematics
1 answer:
Leokris [45]3 years ago
4 0

Answer:

irdk

Step-by-step explanation:

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B. Median

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2 years ago
Find the equation of the form y=ax²+bx+c whose graph passes through the points (1,6), (3, 20), and (−2,15).
Korolek [52]

Answer:

c = \dfrac{25}{4}

b = \dfrac{-13}{8}

a = \dfrac{11}{8}

Step-by-step explanation:

given ,

equation y=ax²+bx+c

passing through points (1,6), (3, 20), and (−2,15).

then these points will satisfy the equation

at (1,6)

y  = a x²+b x+c

6 = a(1)² + b (1) + c

a + b + c = 6------(1)

at (3 , 20)

y  = a x²+b x+c

20 = a(3)² + b (3) + c

9 a + 3 b + c = 20------(2)

at (−2,15)

y  = a x²+b x+c

15 = a(-2)² + b (-2) + c

4 a -2 b + c = 15------(3)

solving equation (1),(2) and (3)

a = 6 - b - c

9 (6 - b - c)+ 3 b + c = 20

6 b + 7 c = 34-------(4)

4 (6 - b - c) -2 b + c = 15

2 b + c = 3----------(5)

on solving equation (4) and (5)

c = \dfrac{25}{4}

b = \dfrac{-13}{8}

a = \dfrac{11}{8}

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3 years ago
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Answer is -4/3
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2 years ago
PLEASE help me. I am stuck on this question for a long time. This is a graph problem
Fofino [41]

Answer:

plot 2

Step-by-step explanation:

put number in order from least to highest:

1 ,3,4,5,8,8,9,11,11,11,14,15,15,18,19,19,19,21,22,23,

from 1 to 5      4 terms

5 to 10             3 terms

from 10 to 15   4 terms (since you can put the 15 in either 10 to 15 or 15to 20)

from 15 to 20  6 terms

from 20 to 25   3

3 0
3 years ago
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